Someone would know the regex expression can be used (in notepad++) in order to replace the first occurence of a characters group in each line?
eg:
abcdefg//ijkl//m.
qsdflkj//sdqlmkf//jqsmdl.
to
abcdefg\\ijkl//m.
qsdflkj\\sdqlmkf//jqsmdl.
so replace //
by \\
in each line, but only the first occurence of , not the next.
If regex can't achieve it, is there another method with notepad. If not, I will code a program to split line and do the job, but need more time.
Thnaks in advance.
Enter this regex in Find what
field
(.*?)//(.*)
Enter this in Replace with
field
$1\\$2
Select Regular expression
in Search Mode
and Uncheck . matches newline
- Ctrl+H
- Find what:
^[^/]+\K//
- Replace with:
\\\\
- check Wrap around
- check Regular expression
- Replace all
Explanation:
^ : begining of line
[^/]+ : 1 or more any character that is not a slash
\K : forget all we have seen until this position
// : 2 slashes
Replacement:
\\\\ : 2 backslashes, each one must be escaped
Result for given example:
abcdefg\\ijkl//m.
qsdflkj\\sdqlmkf//jqsmdl.