How can I use the JSFiddle echo feature with JQuer

问题:

I have read the jsFiddle user's guide for their JSON echo feature but with no luck of producing a working jsFiddle to echo a JSON message using JQuery.

How can I create a jsFiddle to echo the JSON from their guide:

data: {
    json: JSON.encode({
        text: 'some text',
        array: [1, 2, 'three'],
        object: {
            par1: 'another text',
            par2: [3, 2, 'one'],
            par3: {}
        }
    }),
    delay: 3
}

The one example provided is in Mootools which I've never used. So a simple translation from the mootools example into JQuery would be sufficient.

回答1:

var data = {
        json: $.toJSON({
            text: 'some text',
            array: [1, 2, 'three'],
            object: {
                par1: 'another text',
                par2: [3, 2, 'one'],
                par3: {}
            }
        }),
        delay: 3
}


$.ajax({
    url:"/echo/json/",
    data:data,
    type:"POST",
    success:function(response)
    {
       console.log(response);
    }
});

Live Demo

Note I have added na additonal resource.. jquery-json

Demo with FireBug Console on View (no need to pull up developer console to see return)

回答2:

You can also use JSON.stringify

$.ajax({
  url:"/echo/json/",
  data:{
    json: JSON.stringify({
        text: 'some text',
        array: [1, 2, 'three'],
        object: {
            par1: 'another text',
            par2: [3, 2, 'one'],
            par3: {}
        }
      }),
    delay: 3
  },
  type:"POST",
  success:function(response) {
    console.log(response);
  }
});

​

回答3:

Something like this:

$.get('/echo/jsonp/', { foo : 'bar', biz : 'buzz' })
    .success(function(data){ console.log (data) })

JS Fiddle example.

Basically, point the url portion of your $.ajax function at /echo/jsonp/ and you should be set. JSFiddle's docs say that /echo/json/ works, too, but it looks like that particular URL is down at the moment; using the JSONP service without specifying a callback works just fine, though.