Im using Hmisc in rmarkdown file. when I create a table this is what I do
---
output: pdf_document
---
```{r Arrests Stats, results ='asis', message = FALSE, warning = FALSE, echo = FALSE}
# render the table
options(digits=1)
library(Hmisc)
latex(head(mtcars), file="")
```
The latex output has the first row showing as below
%latex.default(cstats, title= title....
\begin{table}...
.
.
.
\end{tabular}
Notice the '%' I need to figure out to remove the first line as it shows on the PDF document when its weaved
Looks like that's hard-coded into latex.default (cat("%", deparse(sys.call()), "%\n", file = file, append = file != "", sep = "") is in the body, with no conditional surrounding it).
I think your best guess then would be to capture.output the cat-d output and strip the comment yourself.
cat(capture.output(latex(head(mtcars), file=''))[-1], sep='\n')
The capture.output catches all the stuff that latex(...) cats, the [-1] removes the first line (being the '%latex.default'), the cat prints out everything else, with newline separator.
You might define your own mylatex to do this, and be a little more clever (e.g. instead of blindly stripping the first line of the output, you could only strip it if it started with '%').
mylatex <- function (...) {
o <- capture.output(latex(...))
# this will strip /all/ line-only comments; or if you're only
# interested in stripping the first such comment you could
# adjust accordingly
o <- grep('^%', o, inv=T, value=T)
cat(o, sep='\n')
}
mylatex(head(mtcars), file='')
