Angular2 get url query parameters

问题:

I'm setting up a Facebook registration for my Angular2 web app. Once the application accepted via Facebook (after being redirected to the Facebook authorization page), it redirect to my webapp with the token and code as url params:

http://localhost:55976/?#access_token=MY_ACCESS_TOKEN&code=MY_CODE

But once the page is loaded, the params are removed. The url become:

http://localhost:55976/

How can I extract the parameters (access_token and code) before they are removed? My routing configuration contains:

{ path: 'login', component: LoginComponent },
{ path: 'login/:access_token/:code', component: LoginComponent },

EDIT:

Here is how I redirect to facebook in my login.component: html:

<a class="btn btn-social btn-facebook socialaccount_provider facebook" title="Facebook" href="#" (click)="login_facebook()">
    <span class="fa fa-facebook"></span> <span style="padding-left:25px">Sign in with Facebook</span>
</a>

Typescript:

login_facebook() {
    let url = 'https://www.facebook.com/dialog/oauth?'+
        'client_id=my_client_id' +
        '&redirect_uri=' + encodeURIComponent('http://localhost:55976/#/login/') +
        '&response_type=code%20token';
    console.log(url);
    window.location.href = url;
}

The facebook api redirect to http://localhost:55976/#/login/, this is where I try to get the access_token and code parameters.

EDIT 2:

If I remove the sharp in the redirect url, facebook redirect me to the good URL, but without the sharp, angular cannot resolve the url.

Before removing '#':

redirect_uri: http://localhost:55976/#/login/
facebook return: http://localhost:55976/?#access_token=MY_ACCESS_TOKEN&code=MY_CODE

After removing '#':

redirect_uri: http://localhost:55976/login/
facebook return: http://localhost:55976/login/?#access_token=MY_ACCESS_TOKEN&code=MY_CODE

That mean that the problem comes from the sharp. But without the sharp, angular returns HTTP Error 404.0 - Not Found.

回答1:

You're looking for query parameters from ActivatedRoute.

To receive them, you could put them into your component's OnInit function like this:

private accesstoken;
private code;

constructor(private route: ActivatedRoute) { }

ngOnInit() {
  // Capture the access token and code
  this.route
      .queryParams
      .subscribe(params => {
          this.accesstoken = params['#access_token'];
          this.code = params['code'];
      });

  // do something with this.code and this.accesstoken
}

There's more examples in the link I put above. You may have problems with angular because the router also identifies fragments, which start with the #... If angular does identify it as a fragment, then you can just subscribe to the fragment observable from ActivatedRoute and do it that way.

I'm not sure if you're being redirected. If you are, the could look into using the preserveQueryParams navigation option, something like this.

this.router.navigate([redirect], {preserveQueryParams: true});

回答2:

Here is my final working code:

Imports:

import { Router, NavigationCancel } from '@angular/router';
import { URLSearchParams, } from '@angular/http';

Constructor:

 constructor(public router: Router) {
    router.events.subscribe(s => {
      if (s instanceof NavigationCancel) {
        let params = new URLSearchParams(s.url.split('#')[1]);
        let access_token = params.get('access_token');
        let code = params.get('code');
      }
    });
  }

回答3:

using Javascript :

(new URL(location)).searchParams.get("parameter_name")

回答4:

getQueryParams( locationSearch: string):any {
    let params = {};
    if( locationSearch ) {
        locationSearch = locationSearch.split('?')[1];
        let splited = locationSearch.split('&');
        for( let i = 0; i < splited.length; i++ ) {
            let propName = splited[i].split('=')[0];
            let propValue = splited[i].split('=')[1];
            params[propName] = propValue;
        }
    }

    return params;
}

let q = getQueryParams( location.search );

回答5:

This works for me! :)

import { ActivatedRoute } from '@angular/router'; 

constructor(private route: ActivatedRoute) { }

/** usage in the method */
let projectId = this.route.snapshot.queryParams.projectId;

回答6:

did you tried this?

import { Params, Router } from '@angular/router';


     constructor(private router: Router) {

            this.route.params.forEach((params: Params) => {
            //here you can get your params
            let param = params['parameterName'];


            })
        }