I am creating test scripts using Python. I need to have a message displayed to the user while the script continues to run. This is to have some status update , for eg: "Saving test results" which should not wait for the user to click "Ok". Essentially , I need to create a message that pops up and closes without the user having to do it.
Currently,I am using easygui module for adding GUI.Easygui can be used for creating such message boxes but they cannot be closed in the code and need to wait for the user to close them for the script to continue running.
Thanks in advance for your time and help.
Kavitha
To forcibly remove on timeout a message box created with easygui you could use .after()
method:
from Tkinter import Tk
from contextlib import contextmanager
@contextmanager
def tk(timeout=5):
root = Tk() # default root
root.withdraw() # remove from the screen
# destroy all widgets in `timeout` seconds
func_id = root.after(int(1000*timeout), root.quit)
try:
yield root
finally: # cleanup
root.after_cancel(func_id) # cancel callback
root.destroy()
Example
import easygui
with tk(timeout=1.5):
easygui.msgbox('message') # it blocks for at most `timeout` seconds
easygui
is not very suitable for your use case. Consider
unittestgui.py or Jenkins.
If you have started to create a GUI, you should be able to use the textbox()
function. A text box could be used as a place for your status messages, rather than making a separate dialog window appear.
I got the following description of textbox()
here:
textbox(msg='', title=' ', text='', codebox=0)
Display some text in a
proportional font with line wrapping at word breaks. This function is
suitable for displaying general written text. The text parameter
should be a string, or a list or tuple of lines to be displayed in the
textbox.