Easiest way to copy all fields from one Python dat

问题:

Let's assume you have defined a Python dataclass:

@dataclass
class Marker:
    a: float
    b: float = 1.0

What's the easiest way to copy the values from an instance marker_a to another instance marker_b?

Here's an example of what I try to achieve:

marker_a = Marker(1.0, 2.0)
marker_b = Marker(11.0, 12.0)
# now some magic happens which you hopefully can fill in
print(marker_b)
# result: Marker(a=1.0, b=2.0)

As a boundary condition, I don't want to create and assign a new instance to marker_b. Ok, I could loop through all defined fields and copy the values one by one, but there has to be a simpler way, I guess.

回答1:

I think that looping over the fields probably is the easiest way. All the other options I can think of involve creating a new object.

from dataclasses import fields

marker_a = Marker(5)
marker_b = Marker(0, 99)

for field in fields(Marker):
    setattr(marker_b, field.name, getattr(marker_a, field.name))

print(marker_b)  # Marker(a=5, b=1.0)

回答2:

@dataclass
class Marker:
    a: float
    b: float = 1.0

marker_a = Marker(0.5)

marker_b = Marker(**m1.__dict__)

marker_b

# Marker(a=0.5, b=1.0)

If you didn't want to create a new instance, try this:

marker_a = Marker(1.0, 2.0)
marker_b = Marker(11.0, 12.0)

marker_b.__dict__ = marker_a.__dict__.copy()

# result: Marker(a=1.0, b=2.0)

Not sure whether that's considered a bad hack though...