Regular Expression to Match Non-Whitespace Charact

2020-04-16 19:49发布

问题:

I need to make a regular expression that matches something like:

JG2144-141/hello

or

!

but not:

laptop bag

or a string consisting of whitespace chars only (' ').

Right now I have [A-Za-z0-9-!/\S], but it isn't working because it still matches with laptop and bag individually. It shouldn't match laptop bag and the empty string at all.

回答1:

The \S in [A-Za-z0-9-!/\S] makes this character class equal to \S, but you want to make sure all chars in the string are non-whitespace chars. That is why you should wrap the pattern with ^ and $ anchors and add a + quantifier after \S to match 1 or more occurrences of this subpattern.

You may use

^\S+$

See the regex demo

Details

  • ^ - start of string
  • \S+ - 1 or more non-whitespace chars
  • $ - end of string.