Check if two vectors are equal

问题:

How can I check whether the first "n" elements of two vectors are equal or not?

I tried the following:

#include <iostream>
#include <vector>
#include <iterator>
using namespace std;

typedef vector<double> v_t;

int main(){
    v_t v1,v2;
    int n = 9;

    for (int i = 1; i<10; i++){
        v1.push_back(i);
        v2.push_back(i);
    }
    v1.push_back(11);
    v2.push_back(12);

    if (v1.begin()+n == v2.begin()+n)
        cout << "success" << endl;
    else
        cout << "failure" << endl;
}

Why does it print "failure" and not "success"?

回答1:

Use the std::equal function from the <algorithm> header:

if (std::equal(v1.begin(), v1.begin() + n, v2.begin())
  std::cout << "success" << std::endl;

Note that both vectors must have at least n elements in them. If either one is too short, behavior of your program will be undefined.

If you want to check whether the entire vector is equal to the other, just compare them like you'd compare anything else:

if (v1 == v2)

Your (failed) code was comparing an iterator of one vector with an iterator of the other. Iterators of equal vectors are not equal. Each iterator is tied to the sequence it's iterating, so an iterator from one vector will never be equal to the iterator of another.

回答2:

The easiest (in terms of fewest non-everyday functions to look up) way to compare the two is to loop again:

bool are_equal = true;
for (int i = 0; i < first_how_many; i++)
    if (v1[i] != v2[i])
    {
        are_equal = false;
        break;
    }

It'll do much the same thing, but if you prefer you can use the <algorithm> header's std::equal function: http://www.cplusplus.com/reference/algorithm/equal/