How to replace all occurrences of a string in Java

问题:

I have this string:

\"Test abc test test abc test test test abc test test abc\"

Doing

str = str.replace(\'abc\', \'\');

seems to only remove the first occurrence of abc in the string above. How can I replace all occurrences of it?

回答1:

For the sake of completeness, I got to thinking about which method I should use to do this. There are basically two ways to do this as suggested by the other answers on this page.

Note: In general, extending the built-in prototypes in JavaScript is generally not recommended. I am providing as extensions on the String prototype simply for purposes of illustration, showing different implementations of a hypothetical standard method on the String built-in prototype.

---

Regular Expression Based Implementation

String.prototype.replaceAll = function(search, replacement) {
    var target = this;
    return target.replace(new RegExp(search, \'g\'), replacement);
};

Split and Join (Functional) Implementation

String.prototype.replaceAll = function(search, replacement) {
    var target = this;
    return target.split(search).join(replacement);
};

---

Not knowing too much about how regular expressions work behind the scenes in terms of efficiency, I tended to lean toward the split and join implementation in the past without thinking about performance. When I did wonder which was more efficient, and by what margin, I used it as an excuse to find out.

On my Chrome Windows 8 machine, the regular expression based implementation is the fastest, with the split and join implementation being 53% slower. Meaning the regular expressions are twice as fast for the lorem ipsum input I used.

Check out this benchmark running these two implementations against each other.

---

As noted in the comment below by @ThomasLeduc and others, there could be an issue with the regular expression-based implementation if search contains certain characters which are reserved as special characters in regular expressions. The implementation assumes that the caller will escape the string beforehand or will only pass strings that are without the characters in the table in Regular Expressions (MDN).

MDN also provides an implementation to escape our strings. It would be nice if this was also standardized as RegExp.escape(str), but alas, it does not exist:

function escapeRegExp(str) {
  return str.replace(/[.*+?^${}()|[\\]\\\\]/g, \"\\\\$&\"); // $& means the whole matched string
}

We could call escapeRegExp within our String.prototype.replaceAll implementation, however, I\'m not sure how much this will affect the performance (potentially even for strings for which the escape is not needed, like all alphanumeric strings).

回答2:

str = str.replace(/abc/g, \'\');

In response to comment:

var find = \'abc\';
var re = new RegExp(find, \'g\');

str = str.replace(re, \'\');

In response to Click Upvote\'s comment, you could simplify it even more:

function replaceAll(str, find, replace) {
    return str.replace(new RegExp(find, \'g\'), replace);
}

Note: Regular expressions contain special (meta) characters, and as such it is dangerous to blindly pass an argument in the find function above without pre-processing it to escape those characters. This is covered in the Mozilla Developer Network\'s JavaScript Guide on Regular Expressions, where they present the following utility function:

function escapeRegExp(str) {
    return str.replace(/([.*+?^=!:${}()|\\[\\]\\/\\\\])/g, \"\\\\$1\");
}

So in order to make the replaceAll() function above safer, it could be modified to the following if you also include escapeRegExp:

function replaceAll(str, find, replace) {
    return str.replace(new RegExp(escapeRegExp(find), \'g\'), replace);
}

回答3:

Note: Don\'t use this in real code.

As an alternative to regular expressions for a simple literal string, you could use

str = \"Test abc test test abc test...\".split(\"abc\").join(\"\");

The general pattern is

str.split(search).join(replacement)

This used to be faster in some cases than using replaceAll and a regular expression, but that doesn\'t seem to be the case anymore in modern browsers. So, this should really only be used as a quick hack to avoid needing to escape the regular expression, not in real code.

回答4:

Using a regular expression with the g flag set will replace all:

someString = \'the cat looks like a cat\';
anotherString = someString.replace(/cat/g, \'dog\');
// anotherString now contains \"the dog looks like a dog\"

See here also

回答5:

Here\'s a string prototype function based on the accepted answer:

String.prototype.replaceAll = function (find, replace) {
    var str = this;
    return str.replace(new RegExp(find, \'g\'), replace);
};

EDIT

If your find will contain special characters then you need to escape them:

String.prototype.replaceAll = function (find, replace) {
    var str = this;
    return str.replace(new RegExp(find.replace(/[-\\/\\\\^$*+?.()|[\\]{}]/g, \'\\\\$&\'), \'g\'), replace);
};

Fiddle: http://jsfiddle.net/cdbzL/

回答6:

Update:

It\'s somewhat late for an update, but since I just stumbled on this question, and noticed that my previous answer is not one I\'m happy with. Since the question involved replaceing a single word, it\'s incredible nobody thought of using word boundaries (\\b)

\'a cat is not a caterpillar\'.replace(/\\bcat\\b/gi,\'dog\');
//\"a dog is not a caterpillar\"

This is a simple regex that avoids replacing parts of words in most cases. However, a dash - is still considered a word boundary. So conditionals can be used in this case to avoid replacing strings like cool-cat:

\'a cat is not a cool-cat\'.replace(/\\bcat\\b/gi,\'dog\');//wrong
//\"a dog is not a cool-dog\" -- nips
\'a cat is not a cool-cat\'.replace(/(?:\\b([^-]))cat(?:\\b([^-]))/gi,\'$1dog$2\');
//\"a dog is not a cool-cat\"

---

basically, this question is the same as the question here: Javascript replace " ' " with " '' "

@Mike, check the answer I gave there... regexp isn\'t the only way to replace multiple occurrences of a subsrting, far from it. Think flexible, think split!

var newText = \"the cat looks like a cat\".split(\'cat\').join(\'dog\');

Alternatively, to prevent replacing word parts -which the approved answer will do, too! You can get around this issue using regular expressions that are, I admit, somewhat more complex and as an upshot of that, a tad slower, too:

var regText = \"the cat looks like a cat\".replace(/(?:(^|[^a-z]))(([^a-z]*)(?=cat)cat)(?![a-z])/gi,\"$1dog\");

The output is the same as the accepted answer, however, using the /cat/g expression on this string:

var oops = \'the cat looks like a cat, not a caterpillar or coolcat\'.replace(/cat/g,\'dog\');
//returns \"the dog looks like a dog, not a dogerpillar or cooldog\" ?? 

Oops indeed, this probably isn\'t what you want. What is, then? IMHO, a regex that only replaces \'cat\' conditionally. (ie not part of a word), like so:

var caterpillar = \'the cat looks like a cat, not a caterpillar or coolcat\'.replace(/(?:(^|[^a-z]))(([^a-z]*)(?=cat)cat)(?![a-z])/gi,\"$1dog\");
//return \"the dog looks like a dog, not a caterpillar or coolcat\"

My guess is, this meets your needs. It\'s not fullproof, of course, but it should be enough to get you started. I\'d recommend reading some more on these pages. This\'ll prove useful in perfecting this expression to meet your specific needs.

http://www.javascriptkit.com/jsref/regexp.shtml

http://www.regular-expressions.info

---

Final addition:

Given that this question still gets a lot of views, I thought I might add an example of .replace used with a callback function. In this case, it dramatically simplifies the expression and provides even more flexibility, like replacing with correct capitalisation or replacing both cat and cats in one go:

\'Two cats are not 1 Cat! They\\\'re just cool-cats, you caterpillar\'
   .replace(/(^|.\\b)(cat)(s?\\b.|$)/gi,function(all,char1,cat,char2)
    {
       //check 1st, capitalize if required
       var replacement = (cat.charAt(0) === \'C\' ? \'D\' : \'d\') + \'og\';
       if (char1 === \' \' && char2 === \'s\')
       {//replace plurals, too
           cat = replacement + \'s\';
       }
       else
       {//do not replace if dashes are matched
           cat = char1 === \'-\' || char2 === \'-\' ? cat : replacement;
       }
       return char1 + cat + char2;//return replacement string
    });
//returns:
//Two dogs are not 1 Dog! They\'re just cool-cats, you caterpillar

回答7:

Match against a global regular expression:

anotherString = someString.replace(/cat/g, \'dog\');

回答8:

str = str.replace(/abc/g, \'\');

Or try the replaceAll function from here:

What are useful JavaScript methods that extends built-in objects?

str = str.replaceAll(\'abc\', \'\'); OR

var search = \'abc\';
str = str.replaceAll(search, \'\');

EDIT: Clarification about replaceAll availability

The \'replaceAll\' method is added to String\'s prototype. This means it will be available for all string objects/literals.

E.g.

var output = \"test this\".replaceAll(\'this\', \'that\');  //output is \'test that\'.
output = output.replaceAll(\'that\', \'this\'); //output is \'test this\'

回答9:

Say you want to replace all the \'abc\' with \'x\':

let some_str = \'abc def def lom abc abc def\'.split(\'abc\').join(\'x\')
console.log(some_str) //x def def lom x x def

I was trying to think about something more simple than modifying the string prototype.

回答10:

Use a regular expression:

str.replace(/abc/g, \'\');

回答11:

Replacing single quotes:

function JavaScriptEncode(text){
    text = text.replace(/\'/g,\''\')
    // More encode here if required

    return text;
}

回答12:

//loop it until number occurrences comes to 0. OR simply copy/paste

    function replaceAll(find, replace, str) 
    {
      while( str.indexOf(find) > -1)
      {
        str = str.replace(find, replace);
      }
      return str;
    }

回答13:

This is the fastest version that doesn\'t use regular expressions.

Revised jsperf

replaceAll = function(string, omit, place, prevstring) {
  if (prevstring && string === prevstring)
    return string;
  prevstring = string.replace(omit, place);
  return replaceAll(prevstring, omit, place, string)
}

It is almost twice as fast as the split and join method.

As pointed out in a comment here, this will not work if your omit variable contains place, as in: replaceAll(\"string\", \"s\", \"ss\"), because it will always be able to replace another occurrence of the word.

There is another jsperf with variants on my recursive replace that go even faster (http://jsperf.com/replace-all-vs-split-join/12)!

• Update July 27th 2017: It looks like RegExp now has the fastest performance in the recently released Chrome 59.

回答14:

str = str.replace(new RegExp(\"abc\", \'g\'), \"\");

worked better for me than the above answers. so new RegExp(\"abc\", \'g\') creates a RegExp what matches all occurence (\'g\' flag) of the text (\"abc\"). The second part is what gets replaced to, in your case empty string (\"\"). str is the string, and we have to override it, as replace(...) just returns result, but not overrides. In some cases you might want to use that.

回答15:

If what you want to find is already in a string, and you don\'t have a regex escaper handy, you can use join/split:

    function replaceMulti(haystack, needle, replacement)
    {
        return haystack.split(needle).join(replacement);
    }

    someString = \'the cat looks like a cat\';
    console.log(replaceMulti(someString, \'cat\', \'dog\'));

回答16:

function replaceAll(str, find, replace) {
  var i = str.indexOf(find);
  if (i > -1){
    str = str.replace(find, replace); 
    i = i + replace.length;
    var st2 = str.substring(i);
    if(st2.indexOf(find) > -1){
      str = str.substring(0,i) + replaceAll(st2, find, replace);
    }       
  }
  return str;
}

回答17:

Using RegExp in JavaScript could do the job for you, just simply do something like below:

var str =\"Test abc test test abc test test test abc test test abc\";
str = str.replace(/abc/g, \'\');

If you think of reuse, create a function to do that for you, but it\'s not recommended as it\'s only one line function, but again if you heavily get use of this, you can write something like this:

String.prototype.replaceAll = String.prototype.replaceAll || function(string, replaced) {
  return this.replace(new RegExp(string, \'g\'), replaced);
};

and simply use it in your code over and over like below:

var str =\"Test abc test test abc test test test abc test test abc\";
str = str.replaceAll(\'abc\', \'\');

But as I mention earlier, it won\'t make a huge difference in terms of lines to be written or performance, only caching the function may effect some faster performance on long strings and also a good practice of DRY code if you want to reuse.

回答18:

var str = \"ff ff f f a de def\";
str = str.replace(/f/g,\'\');
alert(str);

http://jsfiddle.net/ANHR9/

回答19:

while (str.indexOf(\'abc\') !== -1)
{
    str = str.replace(\'abc\', \'\');
}

回答20:

I like this method (it looks a little cleaner):

text = text.replace(new RegExp(\"cat\",\"g\"), \"dog\"); 

回答21:

Just follow this oneliner regex adding the case-sensitivity, so if you do \"ABC\", it would act the same as that for \"abc\".

str = str.replace(/abc/gi, \"\");

回答22:

If the string contain similar pattern like abccc, you can use this:

str.replace(/abc(\\s|$)/g, \"\")

回答23:

If you are trying to ensure that the string you are looking for won\'t exist even after the replacement, you need to use a loop.

For example:

var str = \'test aabcbc\';
str = str.replace(/abc/g, \'\');

When complete, you will still have \'test abc\'!

The simplest loop to solve this would be:

var str = \'test aabcbc\';
while (str != str.replace(/abc/g, \'\')){
   str.replace(/abc/g, \'\');
}

But that runs the replacement twice for each cycle. Perhaps (at risk of being voted down) that can be combined for a slightly more efficient but less readable form:

var str = \'test aabcbc\';
while (str != (str = str.replace(/abc/g, \'\'))){}
// alert(str); alerts \'test \'!

This can be particularly useful when looking for duplicate strings.
For example, if we have \'a,,,b\' and we wish to remove all duplicate commas.
[In that case, one could do .replace(/,+/g,\',\'), but at some point the regex gets complex and slow enough to loop instead.]

回答24:

var string  = \'Test abc Test abc Test abc Test abc\'
string = string.replace(/abc/g, \'\')
console.log(string)

回答25:

Just add /g

document.body.innerHTML = document.body.innerHTML.replace(\'hello\', \'hi\');

to

// Replace \'hello\' string with /hello/g regular expression.
document.body.innerHTML = document.body.innerHTML.replace(/hello/g, \'hi\');

/g means global

回答26:

You can simply use below method

/**
 * Replace all the occerencess of $find by $replace in $originalString
 * @param  {originalString} input - Raw string.
 * @param  {find} input - Target key word or regex that need to be replaced.
 * @param  {replace} input - Replacement key word
 * @return {String}       Output string
 */
function replaceAll(originalString, find, replace) {
  return originalString.replace(new RegExp(find, \'g\'), replace);
};

回答27:

Although people have mentioned the use of regex but there\'s a better approach if you want to replace the text irrespective of the case of the text. Like uppercase or lowercase. Use below syntax

//Consider below example
originalString.replace(/stringToBeReplaced/gi, \'\');

//Output will be all the occurrences removed irrespective of casing.

You can refer the detailed example here.

回答28:

The previous answers are way too complicated. Just use the replace function like this:

str.replace(/your_regex_pattern/g, replacement_string);

Example:

var str = \"Test abc test test abc test test test abc test test abc\";

var res = str.replace(/[abc]+/g, \"\");

console.log(res);

回答29:

You could try combining this two powerful methods.

\"test abc test test abc\".split(\"abc\").join(\"\")

Hope it helps!

回答30:

The following function works for me:

String.prototype.replaceAllOccurence = function(str1, str2, ignore)
{
    return this.replace(new RegExp(str1.replace(/([\\/\\,\\!\\\\\\^\\$\\{\\}\\[\\]\\(\\)\\.\\*\\+\\?\\|\\<\\>\\-\\&])/g,\"\\\\$&\"),(ignore?\"gi\":\"g\")),(typeof(str2)==\"string\")?str2.replace(/\\$/g,\"$$$$\"):str2);
} ;

Now call the functions like this:

\"you could be a Project Manager someday, if you work like this.\".replaceAllOccurence (\"you\", \"I\");

Simply copy and paste this code in your browser console to TEST.