Filter array of objects by array of ids

问题:

I have an array activeIds of ids of services and there is another array servicesList which contains objects of services.

Example: -

activeIds = [202, 204]
serviceList = [{  
                "id":201,
                "title":"a"
               },
               {  
                "id":202,
                "title":"a"
               },
               {  
                "id":203,
                "title":"c"
               },
               {  
                "id":204,
                "title":"d"
               },
               {  
                "id":205,
                "title":"e"
               }];

I want all the services(obj) whose ids are not a part of the first array i.e., activeIds. From the above example code I want service obj of ids 201,203,205

Final output -

expectedArray = [{  
                "id":201,
                "title":"a"
               },
               {  
                "id":203,
                "title":"c"
               },
               {  
                "id":205,
                "title":"e"
               }];

Here is my attempt to code. But it is not correct at all. Please help-

    const activeIds = e; // [202, 204]
    const obj = [];
    this.serviceList.map((s: IService) => {
        activeIds.map((id: number) => {
            if (id !== s.id) {
                obj.push(s);
            }
        });
    });

回答1:

You can simply use array.filter with indexOf to check the matching element in the next array.

var arr = serviceList.filter(function(item){
  return activeIds.indexOf(item.id) === -1;
});

DEMO

let activeIds = [202, 204]
let serviceList = [{  
                "id":201,
                "title":"a"
               },
               {  
                "id":202,
                "title":"a"
               },
               {  
                "id":203,
                "title":"c"
               },
               {  
                "id":204,
                "title":"d"
               },
               {  
                "id":205,
                "title":"e"
               }];


let  arr = serviceList.filter(function(item){
      return activeIds.indexOf(item.id) === -1;
    });
    
console.log(arr);

回答2:

You can do this with filter and includes methods.

const activeIds = [202, 204]
const serviceList = [{"id":201,"title":"a"},{"id":202,"title":"a"},{"id":203,"title":"c"},{"id":204,"title":"d"},{"id":205,"title":"e"}]

const result = serviceList.filter(({id}) => !activeIds.includes(id));
console.log(result)

回答3:

Use filter & indexOf method.indexOf will check if the current id is present in activeIds array

var activeIds = [202, 204]
var serviceList = [{
    "id": 201,
    "title": "a"
  },
  {
    "id": 202,
    "title": "a"
  },
  {
    "id": 203,
    "title": "c"
  },
  {
    "id": 204,
    "title": "d"
  },
  {
    "id": 205,
    "title": "e"
  }
];

var filteredArray = serviceList.filter(function(item) {
  return activeIds.indexOf(item.id) === -1

});

console.log(filteredArray)

回答4:

you can combine indexOf to check if the current id is on the active array and filter the array.