Invoke-Command in a background job

2020-04-10 03:18发布

问题:

I have a powershell 2.0 script which should run a command on several servers and process the output. I want to run the command and the processing for each server in a background job.

The comand works without any problems and terminates within half a second or less:

Invoke-Command -ComputerName $client -ScriptBlock { #do some stuff }

But when I run this in a background job, the job doesn't terminate:

Start-Job { Invoke-Command -ComputerName $client -ScriptBlock { #do some stuff } }

Has someone a idea what the problem could be?

回答1:

Looks like you should do it the other way:

http://technet.microsoft.com/en-us/library/hh849698.aspx

To run a background job on a remote computer, use the AsJob parameter that is available on many cmdlets, or use the Invoke-Command cmdlet to run a Start-Job command on the remote computer. For more information, see about_Remote_Jobs.



回答2:

I prefer to use Start-Job to run invoke-command so that I can watch and handle the jobs on the central machine using Get-Job.

When I loop through the "list of remote computers" I use the "current computer name" as the -Name parameter in the Start-Job so that I can watch each job individually and as a group.

Just my two cents from experience.

Edit Example:

$job =
{ 
    $remoteJob = { ##Do Stuff Here }
    Invoke-Command -ComputerName $args[0] -ScriptBlock $remoteJob
}
Start-Job -Name <jobName> -ScriptBlock $job -ArgumentList <remoteComputer>

To your question about why the Job "never finishes" I don't have input other than, make sure the code you are running remotely does actually end.

Hope this helps



回答3:

This will also work, at least in Powershell 5

invoke-command -asjob -computer $PC -scriptblock { ## do stuff }


回答4:

For Latest version of PS you can create a New Session and use it with Invoke-Command start-job cmdlets instead of using the ComputerName arguments directly.

$s = new-pssession -computername Server01
invoke-command -session $s -scriptblock { start-job -scriptblock {get-eventlog system}}