Using COALESCE to handle NULL values in PostgreSQL

问题:

I have the following query

SELECT  DISTINCT 
     pt.incentive_marketing, 
     pt.incentive_channel, 
     pt.incentive_advertising 
FROM test.pricing pt 
WHERE pt.contract_id = 90000 
group by 1,2,3 
order by pt.incentive_marketing;

The above query returns the o/p as shown in the attached image

However I want to replace all null values by 0 using COALESCE Please let me know how this can be achieved in above SELECT query

Now I further modified the query using coalesce as below

SELECT  
     COALESCE( pt.incentive_marketing, '0' ), 
     COALESCE(pt.incentive_channel,'0'), 
     COALESCE( pt.incentive_advertising,'0') 
FROM test.pricing pt 
WHERE pt.contract_id = 90000 
group by 1,2,3 

the result of which is as attached in image 2.

I still receive one row with blank values

回答1:

You can use COALESCE in conjunction with NULLIF for a short, efficient solution:

COALESCE( NULLIF(yourField,'') , '0' )

The NULLIF function will return null if yourField is equals to the second value ('' in this case), making the COALESCE function fully working on all cases:

                 QUERY                     |                RESULT 
---------------------------------------------------------------------------------
SELECT COALESCE(NULLIF(null  ,''),'0')     |                 '0'
SELECT COALESCE(NULLIF(''    ,''),'0')     |                 '0'
SELECT COALESCE(NULLIF('foo' ,''),'0')     |                 'foo'

回答2:

If you're using 0 and an empty string '' and null to designate undefined you've got a data problem. Just update the columns and fix your schema.

UPDATE pt.incentive_channel
SET   pt.incentive_marketing = NULL
WHERE pt.incentive_marketing = '';

UPDATE pt.incentive_channel
SET   pt.incentive_advertising = NULL
WHERE pt.incentive_marketing = '';

UPDATE pt.incentive_channel
SET   pt.incentive_channel = NULL
WHERE pt.incentive_marketing = '';

This will make joining and selecting substantially easier moving forward.