Had a coworker ask me this, and in my brain befuddled state I didn't have an answer:
Why is it that you can do:
string ham = "ham " + 4;
But not:
string ham = 4;
If there's an implicit cast/operation for string conversion when you are concatenating, why not the same when assigning it as a string? (Without doing some operator overloading, of course)
When concatenating the compiler turns the statement "ham" + 4
into a call to String.Concat
, which takes two object
parameters, so the value 4
is boxed and then ToString
is called on that.
For the assignment there is no implicit conversion from int
to string
, and thus you cannot assign 4
to a string
without explicitly converting it.
In other words the two assignments are handled very differently by the compiler, despite the fact that they look very similar in C#.
Binary + operators are predefined for
numeric and string types. For numeric
types, + computes the sum of its two
operands. When one or both operands
are of type string, + concatenates the
string representations of the
operands.
Reference
The assignment operator (=) stores the
value of its right-hand operand in the
storage location, property, or indexer
denoted by its left-hand operand and
returns the value as its result. The
operands must be of the same type (or
the right-hand operand must be
implicitly convertible to the type of
the left-hand operand).
Reference
There is no implicit conversion when doing concatenation. String concatenation resolves down to a String.Concat call, which has an overload which takes Objects. It is this overload which performs an (explicit) conversion to string.
The value of the righthand side of the first expression is a string, while the value of the righthand side of the second expression is not. The concatonation is providing the magic in the first scenario, where the assignment isn't doing anything special. In the second scenario, the assignment continues to play dumb.
The expression
"ham " + 4
Forces an implicit conversion of 4 to a string based on the combination of a string type and the addition operator. Specifically it's a quality of the "+" operator, and when doing operator overloading you can manually implement the same type of thing.
A similar and less obvious example would be:
long myNumber = Int64.MaxValue - 1;
In this case "1" should be evaluated as a 32-bit integer but it is implicitly converted. You can check the C# language spec section 6.1 for an exhaustive list of implicit conversions supported by the compiler.
edit: to be clear, the language spec section i referred to lists implicit conversions supported by the compiler, while operators like "+" can have their own supported conversions.