I have this xml file:
Response: <ns3:ExecuteResponse xmlns:ns3="http://www.opengis.net/wps/1.0.0" xmlns:ns1="net/ows/1.1" xmlns:ns2="http://www.w3.org/1999/xlink" statusLocation="xxxxf62" serviceInstance="http:/http-post" version="1.0.0" service="xxx">
<ns3:Process ns3:processVersion="0.2">
<ns1:Identifier>OM_B</ns1:Identifier>
<ns1:Title xml:lang="en-US">Bioclim</ns1:Title>
<ns1:Abstract xml:lang="en-US">yyyyyyyyyyyyyyyy</ns1:Abstract>
</ns3:Process>
<ns3:Status creationTime="2010-07-06T17:38:13.355+02:00">
<ns3:ProcessAccepted>ProcessConfiguration has been accepted.</ns3:ProcessAccepted>
</ns3:Status>
<ns3:ProcessOutputs />
</ns3:ExecuteResponse>
How I can extract statusLocation attribute in ExecuteResponse node?
Have you received this XML file via an XMLHttpRequest
? If so, you can use its responseXML
property.
alert(xhr.responseXML.documentElement.getAttribute("statusLocation"));
Or with jQuery:
$.ajax({
type: "GET",
url: "yourfile.xml",
dataType: "xml",
success: function(xml) {
alert(xml.documentElement.getAttribute("statusLocation"));
}
});
Here is one way to do it:
var xml = null;
function loadXML(myURL){
$.ajax({
type: "GET",
url: myURL,
dataType: ($.browser.msie) ? "text" : "xml",
error: function(){
return;
},
success: function(data){
if (typeof data == "string") {
xml = new ActiveXObject("Microsoft.XMLDOM");
xml.async = false;
xml.loadXML(data);
} else {
xml = data;
}
}
});
};
$(loadXML("common/glossary.xml"));
then
$(xml).find('something')