Using variable in PHP exec [closed]

问题:

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Closed 7 years ago.

I want to use my variables in my PHP exec function:

exec('ffmpeg -i $audio_input $audio_output');

What is the right way of doing this? I dont want to change the ffmpeg script. Is it possible?

Thanks

回答1:

Use double quotes instead of single quotes:

exec("ffmpeg -i $audio_input $audio_output");

But please, go read this page: http://php.net/manual/en/language.types.string.php

回答2:

Replace with double quotes:

exec("ffmpeg -i $audio_input $audio_output");

Check the manual for Strings here.

回答3:

Use double quotes like mentioned before or

exec('ffmpeg -i '.$audio_input.' '.$audio_output);