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Closed 6 years ago.
I'm looking to write a library that "parses" information like facebook does when you post a link. However as I don't want to reinvent the wheel does anyone know of a library or and effort to write an Library that does this already?
I have included an example so that you can get a grasp of what I mean if you don't use face book. http://lh4.ggpht.com/_zbED-KN_ZAI/Sx6LuDmZkVI/AAAAAAAADLs/mN7eFnzL1gE/s144/example.png
Haven't seen any library for that, but looks a pretty simple thing. I've jot down a quick function which can help you out. I have kept it simple, you might want to use cURL to fetch the content, put some error handling, etc.
Anyway, here is my two cents:
<?php
function getLinkInfo($url)
{
// Get target link html
$html = file_get_contents($url);
// Prepare the DOM document
$dom = new DOMDocument();
$dom->loadHTML($html);
$dom->preserveWhiteSpace = false;
// Get page title
$titles = $dom->getElementsByTagname('title');
foreach ($titles as $title) {
$linkTitle = $title->nodeValue;
}
// Get META tags
$metas = $dom->getElementsByTagname('meta');
// We only need description
foreach ($metas as $meta) {
if ($meta->getAttribute("name") == "description") {
$linkDesc = $meta->getAttribute("content");
}
}
// Get all images
$imgs = $dom->getElementsByTagname('img');
// Again, we need the first one only
foreach ($imgs as $img) {
$firstImage = $img->getAttribute("src");
if (strpos("http://", $firstImage) === false) {
$firstImage = $url . $firstImage;
}
break;
}
$output = <<<HTML
<div class="info">
<div class="image"><img src="{$firstImage}" alt="{$linkTitle}" /></div>
<div class="desc">
<div class="title">{$linkTitle}</div>
<div class="subtitle">{$url}</div>
<div class="summary">{$linkDesc}</div>
</div>
</div>
HTML;
return $output;
}
echo getLinkInfo("http://www.phpfour.com/");
John Gruber has a regex pattern that might help:
A common programming problem:
identify the URLs in an arbitrary
string of text, where by “arbitrary”
let’s agree we mean something
unstructured such as an email message
or a tweet.
