Python-Scapy or the like-How can I create an HTTP

问题:

I am a moderate programmer, just getting into network programming.

As an attempt to improve my understanding of networks in general, I am trying to perform several basic HTTP actions from the packet level. My question is this: How might I use a library such as SCAPY to build an HTTP GET request and assosciated items at the packet level? I realise this may sound odd, but I can't seem to find any information detailing it, and my own attempts with PAROS and Ethereal have been... Less than satisfactory.

Thanks for any offered help!

Trimiert

回答1:

If you want to do a full three-way handshake, you'll have to do it manually.

Start with your SYN packet:

>>> syn = IP(dst='www.google.com') / TCP(dport=80, flags='S')
>>> syn
<IP  frag=0 proto=tcp dst=Net('www.google.com') |<TCP  dport=www flags=S |>>

Then receive the SYN-ACK packet from the server, sr1 works. Then send your HTTP GET request:

>>> syn_ack = sr1(syn)
Begin emission:
Finished to send 1 packets.
*
Received 1 packets, got 1 answers, remaining 0 packets

>>> syn_ack
<IP  version=4L ihl=5L tos=0x0 len=44 id=424 flags= frag=0L ttl=55 proto=tcp chksum=0x2caa src=74.125.226.148 dst=10.20.30.40 options=[] |<TCP  sport=www dport=ftp_data seq=3833491143 ack=1 dataofs=6L reserved=0L flags=SA window=5720 chksum=0xd8b6 urgptr=0 options=[('MSS', 1430)] |<Padding  load='\x00\x00' |>>>

Then set your TCP sequence and ack numbers and send the GET:

getStr = 'GET / HTTP/1.1\r\nHost: www.google.com\r\n\r\n'
request = IP(dst='www.google.com') / TCP(dport=80, sport=syn_ack[TCP].dport,
             seq=syn_ack[TCP].ack, ack=syn_ack[TCP].seq + 1, flags='A') / getStr
reply = sr1(request)

回答2:

Have you had a look at the tutorial? Just copying and pasting, this looks like it's going to assemble an HTTP request:

>>>  a=Ether()/IP(dst="www.slashdot.org")/TCP()/"GET /index.html HTTP/1.0 \n\n"