double[,] type, how to get the # of rows? [duplica

问题:

This question already has answers here:

How do you get the width and height of a multi-dimensional array? (5 answers)

Closed 2 years ago.

I seem to be getting an odd value.

How do I get the number of rows in my array:

double[,] lookup = { {1,2,3}, {4,5,6} };

The output should be 2.

回答1:

lookup has two dimensions, this is how you can read them

double[,] lookup = { {1,2,3}, {4,5,6} };

int rows = lookup.GetLength(0); // 2
int cols = lookup.GetLength(1); // 3    
int cells = lookup.Length;      // 6 = 2*3

The concept of rows and cols is just tradition, you might just as well call the first dimension the columns.

Also see this question

回答2:

You want the rank property on the array...

double[,] lookup = { { 1, 2, 3 }, { 4, 5, 6 } };
Console.WriteLine(lookup.Rank);

This will provide you with the number of dimensions.

Edit:
This will only provide you with the number of dimensions for the array as opposed to the number of primary elements or "rows" see @Henk Holterman's answer for a working solution.

回答3:

I think what you're looking for is:

lookup.GetLength(0);