Why does javascript ES6 Promises continue executio

问题:

As I understand a promise is something that can resolve() or reject() but I was suprised to find out that code in the promise continues to execute after a resolve or reject is called.

I considered resolve or reject being an async-friendly version of exit or return , that would halt all immediate function execution.

Can someone explain the thought behind why the following example sometimes shows the console.log after a resolve call:

var call = function() {
    return new Promise(function(resolve, reject) {
        resolve();
        console.log("Doing more stuff, should not be visible after a resolve!");
    });
};

call().then(function() {
    console.log("resolved");
});

jsbin

回答1:

JavaScript has the concept of "run to completion". Unless an error is thrown, a function is executed until a return statement or its end is reached. Other code outside of the function can't interfere with that (unless, again, an error is thrown).

If you want resolve() to exit your initialiser function, you have to prepend it by return:

return new Promise(function(resolve, reject) {
    return resolve();
    console.log("Not doing more stuff after a return statement");
});

回答2:

The callbacks that will be invoked when you resolve a promise are still required by the specification to be called asynchronously. This is to ensure consistent behaviour when using promises for a mix of synchronous and asynchronous actions.

Therefore when you invoke resolve the callback is queued, and function execution continues immediately with any code following the resolve() call.

Only once the JS event loop is given back control can the callback be removed from the queue and actually invoked.