Coloring a geom_histogram by gradient

2020-03-19 05:24发布

问题:

I'm trying to plot a geom_histogram where the bars are colored by a gradient.

This is what I'm trying to do:

library(ggplot2)
set.seed(1)
df <- data.frame(id=paste("ID",1:1000,sep="."),val=rnorm(1000),stringsAsFactors=F)
ggplot(df,aes_string(x="val",y="..count..+1",fill="val"))+geom_histogram(binwidth=1,pad=TRUE)+scale_y_log10()+scale_fill_gradient2("val",low="darkblue",high="darkred")

But getting:

Any idea how to get it colored by the defined gradient?

回答1:

Not sure you can fill by val because each bar of the histogram represents a collection of points.

You can, however, fill by categorical bins using cut. For example:

ggplot(df, aes(val, fill = cut(val, 100))) +
  geom_histogram(show.legend = FALSE)



回答2:

Just for completeness.

If the colors I'd like to have the gradient on to be manually selected here's what I suggest:

data:

library(ggplot2)
set.seed(1)
df <- data.frame(id=paste("ID",1:1000,sep="."),val=rnorm(1000),stringsAsFactors=F)

colors:

bins <- 10
cols <- c("darkblue","darkred")
colGradient <- colorRampPalette(cols)
cut.cols <- colGradient(bins)
cuts <- cut(df$val,bins)
names(cuts) <- sapply(cuts,function(t) cut.cols[which(as.character(t) == levels(cuts))])

plot:

ggplot(df,aes(val,fill=cut(val,bins)))+geom_histogram(show.legend=FALSE)+scale_color_manual(values=cut.cols,labels=levels(cuts))+scale_fill_manual(values=cut.cols,labels=levels(cuts))