bash round minutes to 5

2020-03-19 02:13发布

问题:

We have this string to retrieve date and time in clean format.

 TIMESTAMP=$(date "+%Y%m%d%H%M")

Is there some inline code that we can use to round the minute to 5 down. So if it is 12:03 it will make it 12:00 and if it is 12:49 it will be 12:45

Thank you!

回答1:

To do this you can subtract the minutes modulo 5 from the total minutes. To print it out:

echo "$(date "+%Y%m%d%H%M") - ($(date +%M)%5)" | bc

To save it to a variable:

my_var=$(echo "$(date "+%Y%m%d%H%M") - ($(date +%M)%5)" | bc)

This relies on your date format string remaining as it is now - a string of numbers.

Example output:

$ date "+%Y%m%d%H%M"
201404010701
$ echo "$(date "+%Y%m%d%H%M") - ($(date +%M)%5)" | bc
201404010700


回答2:

A little string manipulation:

case $TIMESTAMP in 
    *[1234]) TIMESTAMP=${TIMESTAMP%?}0;; 
    *[6789]) TIMESTAMP=${TIMESTAMP%?}5;; 
esac

${TIMESTAMP%?} removes the last character. Ref: http://www.gnu.org/software/bash/manual/bashref.html#Shell-Parameter-Expansion



回答3:

Not exactly bash only but using dateutils' dround utility, it boils down to:

$ dround now -5m
2014-04-01T10:35:00

or with your format specifiers:

$ dround now -5m -f '%Y%m%d%H%M'
201404011035

Disclaimer: I am the author of that project.



回答4:

You can use the integer division and multiply back to get the round value.

$ m=23
$ (( m /= 5, m *= 5 )) && echo $m
20

Integer division just return the integer part of the result, so in the case above is returning 4. Then multiplying by 5 gives 20.

In your case:

$ TIMESTAMP=$(date "+%Y%m%d%H%M")
$ echo $TIMESTAMP
201404011231
$ (( TIMESTAMP /= 5, TIMESTAMP *= 5 ))
$ echo $TIMESTAMP
201404011230

$ TIMESTAMP=$(date "+%Y%m%d%H%M")
$ echo $TIMESTAMP
201404011257
$ (( TIMESTAMP /= 5, TIMESTAMP *= 5 ))
$ echo $TIMESTAMP
201404011255


回答5:

using the remainder operator the we can determine the number of excess minutes, that can then be subtracted from the original:

TIMESTAMP=$(date "+%Y%m%d%H%M")
(( TIMESTAMP -= TIMESTAMP%15 ))
echo $TIMESTAMP

this only works because both 100 and 60 are divisible by 5 if 15 minutes was wanted instead of 5 the expression would be more complex:

(( TIMESTAMP -= TIMESTAMP%100%5 ))


回答6:

The solution of Fedorqui is very smart and versatile:

seconds=$(date +%s) 
echo $seconds $(date --date="@$seconds" +%H:%M:%S) # say 1559449650 # 06:27:30
# (( seconds /= 3600, seconds *= 3600 )) # rounds to this hour
# (( seconds += 3600, seconds /= 3600, seconds *= 3600 )) # rounds to next hour
(( seconds += 1800, seconds /= 1800, seconds *= 1800 )) # rounds to next half of a hour
next_hour=$(date --date="@$seconds" +%H:%M:%S)
echo $seconds $next_hour # say 1559449800 06:30:00