What would be the best way in Python to determine whether a directory is writeable for the user executing the script? Since this will likely involve using the os module I should mention I'm running it under a *nix environment.
问题:
回答1:
Although what Christophe suggested is a more Pythonic solution, the os module does have the os.access function to check access:
os.access('/path/to/folder', os.W_OK)
# W_OK is for writing, R_OK for reading, etc.
回答2:
It may seem strange to suggest this, but a common Python idiom is
It's easier to ask for forgiveness than for permission
Following that idiom, one might say:
Try writing to the directory in question, and catch the error if you don't have the permission to do so.
回答3:
My solution using the tempfile
module:
import tempfile
import errno
def isWritable(path):
try:
testfile = tempfile.TemporaryFile(dir = path)
testfile.close()
except OSError as e:
if e.errno == errno.EACCES: # 13
return False
e.filename = path
raise
return True
回答4:
Stumbled across this thread searching for examples for someone. First result on Google, congrats!
People talk about the Pythonic way of doing it in this thread, but no simple code examples? Here you go, for anyone else who stumbles in:
import sys
filepath = 'C:\\path\\to\\your\\file.txt'
try:
filehandle = open( filepath, 'w' )
except IOError:
sys.exit( 'Unable to write to file ' + filepath )
filehandle.write("I am writing this text to the file\n")
This attempts to open a filehandle for writing, and exits with an error if the file specified cannot be written to: This is far easier to read, and is a much better way of doing it rather than doing prechecks on the file path or the directory, as it avoids race conditions; cases where the file becomes unwriteable between the time you run the precheck, and when you actually attempt to write to the file.
回答5:
If you only care about the file perms, os.access(path, os.W_OK)
should do what you ask for. If you instead want to know whether you can write to the directory, open()
a test file for writing (it shouldn't exist beforehand), catch and examine any IOError
, and clean up the test file afterwards.
More generally, to avoid TOCTOU attacks (only a problem if your script runs with elevated privileges -- suid or cgi or so), you shouldn't really trust these ahead-of-time tests, but drop privs, do the open()
, and expect the IOError
.
回答6:
Check the mode bits:
def isWritable(name):
uid = os.geteuid()
gid = os.getegid()
s = os.stat(dirname)
mode = s[stat.ST_MODE]
return (
((s[stat.ST_UID] == uid) and (mode & stat.S_IWUSR)) or
((s[stat.ST_GID] == gid) and (mode & stat.S_IWGRP)) or
(mode & stat.S_IWOTH)
)
回答7:
Here is something I created based on ChristopheD's answer:
import os
def isWritable(directory):
try:
tmp_prefix = "write_tester";
count = 0
filename = os.path.join(directory, tmp_prefix)
while(os.path.exists(filename)):
filename = "{}.{}".format(os.path.join(directory, tmp_prefix),count)
count = count + 1
f = open(filename,"w")
f.close()
os.remove(filename)
return True
except Exception as e:
#print "{}".format(e)
return False
directory = "c:\\"
if (isWritable(directory)):
print "directory is writable"
else:
print "directory is not writable"
回答8:
if os.access(path_to_folder, os.W_OK) is not True:
print("Folder not writable")
else :
print("Folder writable")
more info about access can be find it here
回答9:
If you need to check the permission of another user (yes, I realize this contradicts the question, but may come in handy for someone), you can do it through the pwd
module, and the directory's mode bits.
Disclaimer - does not work on Windows, as it doesn't use the POSIX permissions model (and the pwd
module is not available there), e.g. - solution only for *nix systems.
Note that a directory has to have all the 3 bits set - Read, Write and eXecute.
Ok, R is not an absolute must, but w/o it you cannot list the entries in the directory (so you have to know their names). Execute on the other hand is absolutely needed - w/o it the user cannot read the file's inodes; so even having W, without X files cannot be created or modified. More detailed explanation at this link.
Finally, the modes are available in the stat
module, their descriptions are in inode(7) man.
Sample code how to check:
import pwd
import stat
import os
def check_user_dir(user, directory):
dir_stat = os.stat(directory)
user_id, group_id = pwd.getpwnam(user).pw_uid, pwd.getpwnam(user).pw_gid
directory_mode = dir_stat[stat.ST_MODE]
# use directory_mode as mask
if user_id == dir_stat[stat.ST_UID] and stat.S_IRWXU & directory_mode == stat.S_IRWXU: # owner and has RWX
return True
elif group_id == dir_stat[stat.ST_GID] and stat.S_IRWXG & directory_mode == stat.S_IRWXG: # in group & it has RWX
return True
elif stat.S_IRWXO & directory_mode == stat.S_IRWXO: # everyone has RWX
return True
# no permissions
return False
回答10:
I ran into this same need while adding an argument via argparse. The built in type=FileType('w')
wouldn't work for me as I was looking for a directory. I ended up writing my own method to solve my problem. Here is the result with argparse snippet.
#! /usr/bin/env python
import os
import argparse
def writable_dir(dir):
if os.access(dir, os.W_OK) and os.path.isdir(dir):
return os.path.abspath(dir)
else:
raise argparse.ArgumentTypeError(dir + " is not writable or does not exist.")
parser = argparse.ArgumentParser()
parser.add_argument("-d","--dir", type=writable_dir(), default='/tmp/',
help="Directory to use. Default: /tmp")
opts = parser.parse_args()
That results in the following:
$ python dir-test.py -h
usage: dir-test.py [-h] [-d DIR]
optional arguments:
-h, --help show this help message and exit
-d DIR, --dir DIR Directory to use. Default: /tmp
$ python dir-test.py -d /not/real
usage: dir-test.py [-h] [-d DIR]
dir-test.py: error: argument -d/--dir: /not/real is not writable or does not exist.
$ python dir-test.py -d ~
I went back and added print opts.dir to the end, and everything appears to be functioning as desired.