问题:

Consider that I am extending a class such as:

public class MyComboBox<T> extends JComboBox<T> {

    public MyComboBox() {
        super();
    }

    public MyComboBox(ComboBoxModel<T> model ) {
        super(model);
    }

}

Re-defining the parent's constructors (which are fitting for my new class, of course) is annoying enough, but to also copy each constructors documentation is even worse. Not to mention that it's bad for further inheritance, since I now have to update the documentation multiple times.

Obviously, {@inheritDoc} won't work as I am not overriding anything. This is, however, the behavior I'm looking for. Is there any way to achieve this?

How to inherit the parent constructors documentation?

回答1:

Use the @see tag and put the class & member name. To see how that shows up look at JDocs where you can jump from javadoc to source code.

The exact synatax is:

 @see com.x.y.z.ClassName#methodName()

回答2:

You can not override constructors, therefore there is no need to propagate javadocs. Just explain what the client of your object needs to know about how that particular constructor would contruct the object. If it just passes construction on to an extended object, then say just that.