Specify cython output file

2020-03-08 07:57发布

问题:

It seems that by default setup from distutils.core with cmdclass set to build_ext, compiles a cpp or c file in the current working directory. Is there a way to determine where the generated c code is written to? Otherwise, a repository will be littered with generated code.

For example this file setup.py will write a file example.c to the current working directory:

from distutils.core import setup
from Cython.Build import cythonize

setup(
      ext_modules = cythonize("example.pyx"))

回答1:

You can pass the option build_dir="directory name" to Cythonize

# rest of file as before
setup(
      ext_modules = cythonize("example.pyx",
                              build_dir="build"))

The above code will put the generated c files in the directory "build" (which makes sense, since by default it's where distutils puts temporary object files and so forth when it's building).


My original answer had working, not build_dir. Thanks to @ArthurTacca for pointing out that that no longer seems to be right.



回答2:

after initializing an Extension, the parameters can be set to create c in temp directory.

 module  = Extension("temp", "temp.pyx")
 module.cython_c_in_temp = True 


回答3:

Your setup.py is fine.

To get it to build to a different location, invoke python in the following way:

python setup.py build_ext --build-lib <build directory>

I use the following make rules to automate this:

python_lib_dir=src/lib

cython_output = $(patsubst $(python_lib_dir)/%.pyx,$(python_lib_dir)/%.so, $(shell find $(python_lib_dir) -name '*.pyx'))

$(cython_output):%.so:%.pyx      
    python setup.py build_ext --build-lib $(python_lib_dir)