Most concise way to convert a Set to a Lis

问题:

I am currently doing this:

Set<String> setOfTopicAuthors = ....

List<String> list = Arrays.asList( 
    setOfTopicAuthors.toArray( new String[0] ) );

Can you beat this ?

回答1:

List<String> list = new ArrayList<String>(listOfTopicAuthors);

回答2:

List<String> l = new ArrayList<String>(listOfTopicAuthors);

回答3:

Considering that we have Set<String> stringSet we can use following:

Java 10 (Unmodifiable list)

List<String> strList = stringSet.stream().collect(Collectors.toUnmodifiableList());

Java 8 (Modifiable Lists)

import static java.util.stream.Collectors.*;
List<String> stringList1 = stringSet.stream().collect(toList());

As per the doc for the method toList()

There are no guarantees on the type, mutability, serializability, or thread-safety of the List returned; if more control over the returned List is required, use toCollection(Supplier).

So if we need a specific implementation e.g. ArrayList we can get it this way:

List<String> stringList2 = stringSet.stream().
                              collect(toCollection(ArrayList::new));

Java 8 (Unmodifiable Lists)

We can make use of Collections::unmodifiableList method and wrap the list returned in previous examples. We can also write our own custom method as:

class ImmutableCollector {
    public static <T> Collector<T, List<T>, List<T>> toImmutableList(Supplier<List<T>> supplier) {
            return Collector.of( supplier, List::add, (left, right) -> {
                        left.addAll(right);
                        return left;
                    }, Collections::unmodifiableList);
        }
}

And then use it as:

List<String> stringList3 = stringSet.stream()
             .collect(ImmutableCollector.toImmutableList(ArrayList::new)); 

Another possibility is to make use of collectingAndThen method which allows some final transformation to be done before returning result:

    List<String> stringList4 = stringSet.stream().collect(collectingAndThen(
      toCollection(ArrayList::new),Collections::unmodifiableList));

---

One point to note is that the method Collections::unmodifiableList returns an unmodifiable view of the specified list, as per doc. An unmodifiable view collection is a collection that is unmodifiable and is also a view onto a backing collection. Note that changes to the backing collection might still be possible, and if they occur, they are visible through the unmodifiable view. But the collector method Collectors.unmodifiableList returns truly immutable list in Java 10.

回答4:

Try this for Set:

Set<String> listOfTopicAuthors = .....
List<String> setList = new ArrayList<String>(listOfTopicAuthors); 

Try this for Map:

Map<String, String> listOfTopicAuthors = .....
// List of values:
List<String> mapValueList = new ArrayList<String>(listOfTopicAuthors.values());
// List of keys:
List<String> mapKeyList = new ArrayList<String>(listOfTopicAuthors.KeySet());

回答5:

If you are using Guava, you statically import newArrayList method from Lists class:

List<String> l = newArrayList(setOfAuthors);

回答6:

not really sure what you're doing exactly via the context of your code but...

why make the listOfTopicAuthors variable at all?

List<String> list = Arrays.asList((....).toArray( new String[0] ) );

the "...." represents however your set came into play, whether it's new or came from another location.