how to populate mysql column value based on a form

2020-03-05 04:51发布

问题:

I have created a mysql table with the following columns...

item_price, discount, delivery_charge, grand_total

The value of item_price, discount, and delivery_charge all vary depending on the item under consideration, and these would be filled into the table manually.

I would like to have mysql populate the value in the grand_total column based on the values of item_price, discount, and delivery_charge, using the formula below...

grand_total = item_price - discount + delivery_charge

Can I somehow specify a formula for this column while creating the table structure in mysql? I know this can be done using php, but I prefer the database doing this for me automatically, if possible.

回答1:

Here's an example of a trigger that will work. Note that you'll need both update and insert triggers due to your "ad hoc update" requirements.

delimiter ~

create trigger my_table_update before update on my_table
for each row begin
    set new.grand_total = new.item_price - new.discount + new.delivery_charge;
end~

create trigger my_table_insert before insert on my_table
for each row begin
    set new.grand_total = new.item_price - new.discount + new.delivery_charge;
end~

delimiter ;

But wouldn't a view be simpler and better?

create view my_table_view as
select item_price, discount, delivery_charge, 
item_price - discount + delivery_charge as grand_total
from my_table;

then just select from the view instead of the table



回答2:

I think you'd have to use a BEFORE INSERT trigger for that:

http://dev.mysql.com/doc/refman/5.6/en/create-trigger.html

Something like this (untested off the top of my header code):

CREATE TRIGGER blahblah BEFORE INSERT ON your_table
FOR EACH ROW BEGIN
    set new.grand_total = new.item_price - new.discount + new.delivery_charge;
END;