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问题:
I've come across the following code:
function (data) {
if (data != null && data !== undefined) {
// some code here
}
}
I'm somewhat new to JavaScript, but, from other questions I've been reading here, I'm under the impression that this code does not make much sense.
In particular, this answer states that
You'll get an error if you access an undefined variable in any context other than typeof
.
Update: The (quote of the) answer above may be misleading. It should say «an undeclared variable», instead of «an undefined variable».
As I found out, in the answers by Ryan ♦, maerics, and nwellnhof, even when no arguments are provided to a function, its variables for the arguments are always declared. This fact also proves wrong the first item in the list below.
From my understanding, the following scenarios may be experienced:
The function was called with no arguments, thus making data
an undefined variable, and raising an error on data != null
.
The function was called specifically with null
(or undefined
), as its argument, in which case data != null
already protects the inner code, rendering && data !== undefined
useless.
The function was called with a non-null argument, in which case it will trivially pass both data != null
and data !== undefined
.
Q: Is my understanding correct?
I've tried the following, in Firefox's console:
--
[15:31:31.057] false != null
[15:31:31.061] true
--
[15:31:37.985] false !== undefined
[15:31:37.989] true
--
[15:32:59.934] null != null
[15:32:59.937] false
--
[15:33:05.221] undefined != null
[15:33:05.225] false
--
[15:35:12.231] "" != null
[15:35:12.235] true
--
[15:35:19.214] "" !== undefined
[15:35:19.218] true
I can't figure out a case where the data !== undefined
after data != null
might be of any use.
回答1:
An “undefined variable” is different from the value undefined
.
An undefined variable:
var a;
alert(b); // ReferenceError: b is not defined
A variable with the value undefined
:
var a;
alert(a); // Alerts “undefined”
When a function takes an argument, that argument is always declared even if its value is undefined
, and so there won’t be any error. You are right about != null
followed by !== undefined
being useless, though.
回答2:
In JavaScript, null
is a special singleton object which is helpful for signaling "no value". You can test for it by comparison and, as usual in JavaScript, it's a good practice to use the ===
operator to avoid confusing type coercion:
var a = null;
alert(a === null); // true
As @rynah mentions, "undefined" is a bit confusing in JavaScript. However, it's always safe to test if the typeof(x)
is the string "undefined", even if "x" is not a declared variable:
alert(typeof(x) === 'undefined'); // true
Also, variables can have the "undefined value" if they are not initialized:
var y;
alert(typeof(y) === 'undefined'); // true
Putting it all together, your check should look like this:
if ((typeof(data) !== 'undefined') && (data !== null)) {
// ...
However, since the variable "data" is always defined since it is a formal function parameter, using the "typeof" operator is unnecessary and you can safely compare directly with the "undefined value".
function(data) {
if ((data !== undefined) && (data !== null)) {
// ...
This snippet amounts to saying "if the function was called with an argument which is defined and is not null..."
回答3:
Q: The function was called with no arguments, thus making data an undefined variable, and raising an error on data != null.
A: Yes, data
will be set to undefined. See section 10.5 Declaration Binding Instantiation of the spec. But accessing an undefined value does not raise an error. You're probably confusing this with accessing an undeclared variable in strict mode which does raise an error.
Q: The function was called specifically with null (or undefined), as its argument, in which case data != null already protects the inner code, rendering && data !== undefined useless.
Q: The function was called with a non-null argument, in which case it will trivially pass both data != null and data !== undefined.
A: Correct. Note that the following tests are equivalent:
data != null
data != undefined
data !== null && data !== undefined
See section 11.9.3 The Abstract Equality Comparison Algorithm and section 11.9.6 The Strict Equality Comparison Algorithm of the spec.
回答4:
I think, testing variables for values you do not expect is not a good idea in general. Because the test as your you can consider as writing a blacklist of forbidden values. But what if you forget to list all the forbidden values? Someone, even you, can crack your code with passing an unexpected value. So a more appropriate approach is something like whitelisting - testing variables only for the expected values, not unexpected. For example, if you expect the data value to be a string, instead of this:
function (data) {
if (data != null && data !== undefined) {
// some code here
// but what if data === false?
// or data === '' - empty string?
}
}
do something like this:
function (data) {
if (typeof data === 'string' && data.length) {
// consume string here, it is here for sure
// cleaner, it is obvious what type you expect
// safer, less error prone due to implicit coercion
}
}
回答5:
typeof foo === "undefined"
is different from foo === undefined
, never confuse them. typeof foo === "undefined"
is what you really need. Also, use !==
in place of !=
So the statement can be written as
function (data) {
if (typeof data !== "undefined" && data !== null) {
// some code here
}
}
Edit:
You can not use foo === undefined
for undeclared variables.
var t1;
if(typeof t1 === "undefined")
{
alert("cp1");
}
if(t1 === undefined)
{
alert("cp2");
}
if(typeof t2 === "undefined")
{
alert("cp3");
}
if(t2 === undefined) // fails as t2 is never declared
{
alert("cp4");
}
回答6:
The simple way to do your test is :
function (data) {
if (data) { // check if null, undefined, empty ...
// some code here
}
}
回答7:
var a;
alert(a); //Value is undefined
var b = "Volvo";
alert(b); //Value is Volvo
var c = null;
alert(c); //Value is null