I am trying to expose Java method via Scala (more details on original java method - it is coming from Kafka)
This is original Java method:
public void commitSync(Map<TopicPartition,OffsetAndMetadata> offsets)
How to expose and pass parameters to a method in Scala? I have something like:
def commitSync() = {
consumer.commitSync(...)
}
Thanks.
Your Scala snippet looks correct, this is how I'd fill up the rest of it:
import org.apache.kafka.clients.consumer.{KafkaConsumer, OffsetAndMetadata}
import org.apache.kafka.common.TopicPartition
import collection.mutable.Map
import collection.JavaConverters._
//initialise your consumer the way you want
val consumer = createKafkaConsumer(config, subscriptions)
//you could accept a scala.collection.mutable.Map here
def commitSync(offsets: Map[TopicPartition, OffsetAndMetadata]) = {
//and then convert it to a java.util.Map
consumer.commitSync(offsets.asJava)
}