I have a worksheet that is updated every week with thousands of rows and would need to transfer rows from this worksheet after filtering. I am using the current code to find the cells which has the value I need and then transfer the entire row to another sheet but after saving the file, I get the "IndexError: list index out of range" exception.
The code I use is as follows:
import openpyxl
wb1 = openpyxl.load_workbook('file1.xlsx')
wb2 = openpyxl.load_workbook('file2.xlsx')
ws1 = wb1.active
ws2 = wb2.active
for row in ws1.iter_rows():
for cell in row:
if cell.value == 'TrueValue':
n = 'A' + str(cell.row) + ':' + ('GH' + str(cell.row))
for row2 in ws1.iter_rows(n):
ws2.append(row2)
wb2.save("file2.xlsx")
The original code I used that used to work is below and has to be modified because of the large files which causes MS Excel not to open them (over 40mb).
n = 'A3' + ':' + ('GH'+ str(ws1.max_row))
for row in ws1.iter_rows(n):
ws2.append(row)
Thanks.
Use a list to hold the items in each column for the particular row.
Then append the list to your ws2.
...
def iter_rows(ws,n): #produce the list of items in the particular row
for row in ws.iter_rows(n):
yield [cell.value for cell in row]
for row in ws1.iter_rows():
for cell in row:
if cell.value == 'TrueValue':
n = 'A' + str(cell.row) + ':' + ('GH' + str(cell.row))
list_to_append = list(iter_rows(ws1,n))
for items in list_to_append:
ws2.append(items)
I'm not entirely sure what you're trying to do but I suspect the problem is that you have nested your copy loop.
Try the following:
row_nr = 1
for row in ws1:
for cell in row:
if cell.value == "TrueValue":
row_nr = cell.row
break
if row_nr > 1:
break
for row in ws1.iter_rows(min_row=row_nr, max_col=190):
ws2.append((cell.value for cell in row))
Question: I get the "IndexError: list index out of range" exception.
I get, from ws1.iter_rows(n)
UserWarning: Using a range string is deprecated. Use ws[range_string]
and from ws2.append(row2).
ValueError: Cells cannot be copied from other worksheets
The Reason are row2 does hold a list of Cell objects instead of a list of Values
Question: ... need to transfer rows from this worksheet after filtering
The following do what you want, for instance:
# If you want to Start at Row 2 to append Row Data
# Set Private self._current_row to 1
ws2.cell(row=1, column=1).value = ws2.cell(row=1, column=1).value
# Define min/max Column Range to copy
from openpyxl.utils import range_boundaries
min_col, min_row, max_col, max_row = range_boundaries('A:GH')
# Define Cell Index (0 Based) used to Check Value
check = 0 # == A
for row in ws1.iter_rows():
if row[check].value == 'TrueValue':
# Copy Row Values
# We deal with Tuple Index 0 Based, so min_col must have to be -1
ws2.append((cell.value for cell in row[min_col-1:max_col]))
Tested with Python: 3.4.2 - openpyxl: 2.4.1 - LibreOffice: 4.3.3.2
I was able to solve this with lists for my project.
import openpyxl
#load data file
wb1 = openpyxl.load_workbook('original.xlsx')
sheet1 = wb1.active
print("loaded 1st file")
#new template file
wb2 = openpyxl.load_workbook('blank.xlsx')
sheet2 = wb2.active
print("loaded 2nd file")
header = sheet1[1:1] #grab header row
listH =[]
for h in header:
listH.append(h.value)
sheet2.append(listH)
colOfInterest= 11 # this is my col that contains the value I'm checking against
for rowNum in range(2, sheet1.max_row +1): #iterate over each row, starting with 2 to skipping header from original file
if sheet1.cell(row=rowNum, column=colOfInterest).value is not None: #interested in non blank values in column 11
listA = [] # list which will hold my data
row = sheet1[rowNum:rowNum] #creates a tuple of row's data
#print (str(rowNum)) # for debugging to show what rows are copied
for cell in row: # for each cell in the row
listA.append(cell.value) # add each cell's data as an element in the list
if listA[10] == 1: # condition1 I'm checking for by looking up the index in the list
sheet2.append(listA) # appending the sheet2's next available row
elif listA[10] > 1: # condition2 I'm checking for by looking up the index in the list
# do something else and store it in bar
sheet2.append(bar) # appending the sheet2's next available row
print("saving file...")
wb2.save('result.xlsx') # save file
print("Done!")
Tested with: Python 3.7 openpyxl 2.5.4
