I'd like to use the ZipFile
class to unzip a file using its name from an archive of multiple files. How can I get the string of the zip file name and directory to pass to the ZipFile
constructor?
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试):
问题:
回答1:
You can use the AssetManager and ZipInputStream http://developer.android.com/reference/android/content/res/AssetManager.html
ZipInputStream in = null;
try {
final String zipPath = "data/sample.zip";
// Context.getAssets()
in = new ZipInputStream(getAssets().open(zipPath));
for (ZipEntry entry = in.getNextEntry(); entry != null; entry = in.getNextEntry()) {
// handle the zip entry
}
} catch (IOException e) {
Log.e(TAG, e.getMessage());
} finally {
try {
if (in != null) {
in.close();
}
} catch (IOException ignored) {
}
in = null;
}