I would like to be able to get the format string from a DateTime string.
e.g.
"2012-12-08 15:00:00" => "yyyy-MM-dd HH:mm:ss"
"2013/30/01 16:00" => "yyyy/dd/MM HH:mm"
Is this possible?
I would like to be able to get the format string from a DateTime string.
e.g.
"2012-12-08 15:00:00" => "yyyy-MM-dd HH:mm:ss"
"2013/30/01 16:00" => "yyyy/dd/MM HH:mm"
Is this possible?
It would be very hard to do this in a completely general way, but one option would be to extract the relevant DateTimeFormatInfo
that you're interested in (using CultureInfo.DateTimeFormat
), extract the culture-specific patterns from that (LongDatePattern
, LongTimePattern
etc), combine the patterns appropriately in some cases (e.g. ShortDatePattern
space ShortTimePattern
) and then try each pattern in turn using DateTime.TryParseExact
- remembering to still specify the culture each time in order to handle date separators etc appropriately.
When DateTime.TryParseExact
returns true
, you know you've got a pattern which will parse the given text.
Sample code - including showing an example where you'd expect it to work but it doesn't:
using System;
using System.Collections.Generic;
using System.Globalization;
class Test
{
static void Main()
{
var us = new CultureInfo("en-US");
var uk = new CultureInfo("en-GB");
string text = "07/06/2013 11:22:11";
// This one fails, as there's no appropriate time format
Console.WriteLine(GuessPattern(text, us));
// This one prints dd/MM/yyyy HH:mm:ss
Console.WriteLine(GuessPattern(text, uk));
}
static string GuessPattern(string text, CultureInfo culture)
{
foreach (var pattern in GetDateTimePatterns(culture))
{
DateTime ignored;
if (DateTime.TryParseExact(text, pattern, culture,
DateTimeStyles.None, out ignored))
{
return pattern;
}
}
return null;
}
static IList<string> GetDateTimePatterns(CultureInfo culture)
{
var info = culture.DateTimeFormat;
return new string[]
{
info.FullDateTimePattern,
info.LongDatePattern,
info.LongTimePattern,
info.ShortDatePattern,
info.ShortTimePattern,
info.MonthDayPattern,
info.ShortDatePattern + " " + info.LongTimePattern,
info.ShortDatePattern + " " + info.ShortTimePattern,
info.YearMonthPattern
// Consider the sortable pattern, ISO-8601 etc
};
}
}
You could potentially hard-code some "extra" date and time formats which you expect to work.
EDIT: To handle ambiguity, you could easily make GuessPattern
return an IEnumerable<string>
instead of a single string:
static IEnumerable<string> GuessPatterns(string text, CultureInfo culture)
{
DateTime ignored;
return GetDateTimePatterns(culture)
.Where(pattern => DateTime.TryParseExact(text, pattern, culture,
DateTimeStyles.None, out ignored))
}
}
You can have a set of predefined formats and parse the date and see if it passes, then you can get the string format you are looking for.
Refer to the answer but its in java - How to get the given date string format(pattern) in java?
I had the same idea as Jon Skeet and went to implement it:
// Helper method
IEnumerable<string> DateTimeFormatPatterns(DateTimeFormatInfo format)
{
var accessors = new Func<DateTimeFormatInfo, string>[]
{
f => f.FullDateTimePattern,
f => f.LongDatePattern,
f => f.LongTimePattern,
f => f.MonthDayPattern,
f => f.ShortDatePattern,
f => f.SortableDateTimePattern,
f => f.UniversalSortableDateTimePattern,
f => f.YearMonthPattern,
};
return accessors.Select(accessor => accessor(format));
}
// The real function
string DetectDateTimeFormat(string date, CultureInfo culture)
{
DateTime dummy;
foreach (var pattern in DateTimeFormatPatterns(culture.DateTimeFormat))
{
if (DateTime.TryParseExact(date, pattern, culture,
DateTimeStyles.None, out dummy))
{
return pattern;
}
}
return null;
}
There is space for improvement here (e.g. the hardcoded DateTimeStyles.None
doesn't help, an overload which assumes the current culture would also be useful), but you can use it like this:
var format = DetectDateTimeFormat("2012-12-08 15:00:00",
CultureInfo.CurrentCulture);
You can try by writing the below code to get yyyy/dd/MM HH:mm
format.
DateTimeFormatInfo df1 = new DateTimeFormatInfo();
df1.SortTimePattern();
It would give you same HH:mm
format.