问题:

I am trying to open a raw socket with Python under linux.

My simple code:

s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_IP)
s.bind((HOST, 5454))

And I got this error:

[ERROR] Protocol not supported

By the way, I am using python 2.7.3 under linux 12.04, and I used root to run the code.

Does anyone have a clue?

Update: The solution given by dstromberg is correct. If you want the whole packet, then use his solution. However, there is another combination:

s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_TCP)

that also works.

In this case, you will receive a whole TCP packet with IP and TCP headers on it. If your use dstromberg's solution, you will also see the ethernet header. So it depends on how 'raw' you want your packet to be.

回答1:

Try socket.AF_PACKET instead of socket.AF_INET.

回答2:

This runs without error as root:

#!/usr/local/cpython-3.3/bin/python

import socket as socket_mod

#s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_IP)
socket = socket_mod.socket(socket_mod.AF_PACKET, socket_mod.SOCK_RAW, socket_mod.IPPROTO_IP)
#socket.bind(('localhost', 5454))
socket.bind(('lo', 5454))