Spring: How to get parameters from POST body?

问题:

Web-service using spring in which I have to get the params from the body of my post request? The content of the body is like:-

source=”mysource”

&json=
{
    "items": [
        {
            "username": "test1",
            "allowed": true
        },
        {
            "username": "test2",
            "allowed": false
        }
    ]
}

And the web-service method looks like:-

@RequestMapping(value = "/saveData", headers="Content-Type=application/json", method = RequestMethod.POST)
    @ResponseBody
    public ResponseEntity<Boolean> saveData(@RequestBody String a) throws MyException {
        return new ResponseEntity<Boolean>(uiRequestProcessor.saveData(a),HttpStatus.OK);

    }

Please let me know how do I get the params from the body? I can get the whole body in my string but I don't think that would be a valid approach. Please let me know how do I proceed further.

回答1:

You can get param from request.

@ResponseBody
public ResponseEntity<Boolean> saveData(HttpServletRequest request,
            HttpServletResponse response, Model model){
   String jsonString = request.getParameter("json");
}

回答2:

You can get entire post body into a POJO. Following is something similar

@RequestMapping(value = { "/api/pojo/edit" }, method = RequestMethod.POST, produces = "application/json", consumes = "application/json")
@ResponseBody
public Boolean editWinner( @RequestBody Pojo pojo) { 

Where each field in Pojo (Including getter/setters) should match the Json request object that the controller receives..

回答3:

You can bind the json to a POJO using MappingJacksonHttpMessageConverter . Thus your controller signature can read :-

  public ResponseEntity<Boolean> saveData(@RequestBody RequestDTO req) 

Where RequestDTO needs to be a bean appropriately annotated to work with jackson serializing/deserializing. Your *-servlet.xml file should have the Jackson message converter registered in RequestMappingHandler as follows :-

  <list >
    <bean class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"/>

  </list>
</property>
</bean>

回答4:

In class do like this

@RequestMapping(value = "/saveData", method = RequestMethod.POST)
 @ResponseBody
    public ResponseEntity<Boolean> saveData(HttpServletResponse response,Bean beanName) throws MyException {
        return new ResponseEntity<Boolean>(uiRequestProcessor.saveData(a),HttpStatus.OK);

}

In page do like this:

<form enctype="multipart/form-data" action="<%=request.getContextPath()%>/saveData" method="post" name="saveForm" id="saveForm">
<input type="text" value="${beanName.userName }" id="username" name="userName" />

</from>

回答5:

You will need these imports...

import javax.servlet.*;
import javax.servlet.http.*;

And, if you're using Maven, you'll also need this in the dependencies block of the pom.xml file in your project's base directory.

<dependency>
    <groupId>javax.servlet</groupId>
    <artifactId>javax.servlet-api</artifactId>
    <version>3.0.1</version>
    <scope>provided</scope>
</dependency>

Then the above-listed fix by Jason will work:

@ResponseBody
    public ResponseEntity<Boolean> saveData(HttpServletRequest request,
        HttpServletResponse response, Model model){
        String jsonString = request.getParameter("json");
    }

回答6:

You can try using @RequestBodyParam

@RequestMapping(value = "/saveData", headers="Content-Type=application/json", method = RequestMethod.POST)
@ResponseBody
public ResponseEntity<Boolean> saveData(@RequestBodyParam String source,@RequestBodyParam JsonDto json) throws MyException {
    ...
}

https://github.com/LambdaExpression/RequestBodyParam