I would expect this to be pretty simple. I'm using the lineinfile
module like so:
- name: Update bashrc for PythonBrew for foo user
lineinfile:
dest=/home/foo/.bashrc
backup=yes
line="[[ -s ${pythonbrew.bashrc_path} ]] && source ${pythonbrew.bashrc_path}"
owner=foo
regexp='^'
state=present
insertafter=EOF
create=True
The problem I'm having is that it's replacing the last line in the file (which is fi
) with my new line rather than appending the line. This produces a syntax error.
Do I have the parameters correct? I've tried setting regexp to both '^'
and ''
(blank). Is there another way to go about this?
I'm using Ansible 1.3.3.
Apparently ansible has matured and now (version >2.4.0) according to the documentation, The defaults when only the line is specified will append a given line to the destination file:
- name: Update bashrc for PythonBrew for foo user
lineinfile:
dest=/home/foo/.bashrc
line="[[ -s ${pythonbrew.bashrc_path} ]] && source {pythonbrew.bashrc_path}"
owner=foo
The Ansible discussion group helped get me sorted out on this. The problem is the regexp
parameter.
Since I only want the line appended to the file once, I need the regexp to match the line as closely as possible. This is complicated in my case by the fact that my line includes variables. But, assuming the line started [[ -s $HOME/.pythonbrew
, I found the following to be sufficient:
- name: Update bashrc for PythonBrew for foo user
lineinfile:
dest: /home/foo/.bashrc
line: "[[ -s ${pythonbrew.bashrc_path} ]] && source ${pythonbrew.bashrc_path}"
regexp: "^\[\[ -s \\$HOME/\.pythonbrew"
owner: foo
state: present
insertafter: EOF
create: True