how to check if string contains '+' charac

问题:

This question already has answers here:

How can I check if a single character appears in a string? (16 answers)

Closed 3 years ago.

I want to check if my string contains a + character.I tried following code

s= "ddjdjdj+kfkfkf";

if(s.contains ("\\+"){
 String parts[] = s.split("\\+);
  s=  parts[0]; // i want to strip part after  +

}

but it doesnot give expected result.Any idea?

回答1:

You need this instead:

if(s.contains("+"))

contains() method of String class does not take regular expression as a parameter, it takes normal text.

---

EDIT:

String s = "ddjdjdj+kfkfkf";

if(s.contains("+"))
{
    String parts[] = s.split("\\+");
    System.out.print(parts[0]);
}

OUTPUT:

ddjdjdj

回答2:

Why not just:

int plusIndex = s.indexOf("+");
if (plusIndex != -1) {
    String before = s.substring(0, plusIndex);
    // Use before
}

It's not really clear why your original version didn't work, but then you didn't say what actually happened. If you want to split not using regular expressions, I'd personally use Guava:

Iterable<String> bits = Splitter.on('+').split(s);
String firstPart = Iterables.getFirst(bits, "");

If you're going to use split (either the built-in version or Guava) you don't need to check whether it contains + first - if it doesn't there'll only be one result anyway. Obviously there's a question of efficiency, but it's simpler code:

// Calling split unconditionally
String[] parts = s.split("\\+");
s = parts[0];

Note that writing String[] parts is preferred over String parts[] - it's much more idiomatic Java code.

回答3:

[+]is simpler

    String s = "ddjdjdj+kfkfkf";

    if(s.contains ("+"))
    {
        String parts[] = s.split("[+]");
        s =  parts[0]; // i want to strip part after  +
    }
    System.out.println(s);