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问题:
var A=function(){
};
$.extend(A.prototype, {
init:function(){
alert('A init');
}
});
var B=function(){
};
$.extend(B.prototype,A.prototype,{
init:function(){
alert('B init');
}
});
var p=new A();
p.init();
var x=new B();
x.init();
is the above the best way to create class and inheritance in jQuery? In B's init how do I invoke parent's init (similar to super.init() in OO languages)?
回答1:
For OO, it's best to look outside jQuery. jQuery is based on collections returned by selectors.
If you want classes, some choices are Base2, Joose, and JS.Class.
回答2:
John Resig
created a snippet for simple inheritance here.
http://ejohn.org/blog/simple-javascript-inheritance/
he stores the super class to a _super variable so you can call it like such
this._super();
you can reference his code snippet to get a better idea of what he
another helpful post is:
http://alexsexton.com/?p=51
回答3:
How to invoke parent's methods:
var B=function(){
A.call(this);
};
$.extend(B.prototype,A.prototype,{
init:function(){
A.prototype.init.call(this);
alert('B init');
}
});
回答4:
If you don't want to depend on any other libraries, you can do this:
function A() {}
A.prototype.foo = function() {};
function B() {
A.call(this);
//Or, if there are arguments that need to be passed to A(),
//this might be preferable:
//A.apply(this, arguments);
}
B.prototype = new A();
//Or, if the browser supports ECMAScript 5 and/or you have a shim for Object.create,
//it would be better to do this:
B.prototype = Object.create(A.prototype);
$.extend(B.prototype, {
//set the constructor property back to B, otherwise it would be set to A
constructor: B,
bar: function() {}
});
Make sure to define any properties in the constructor rather than on the prototype, e.g.:
function A() {
this.baz = null;
}
This avoids having unintentionally shared prototype properties.
There are some libraries that make prototypal inheritance easier:
- https://github.com/mbrowne/simpleoo.js
(my library; its documentation expounds on some of the concepts I've mentioned here)
- https://github.com/Gozala/selfish
- https://github.com/Raynos/pd
Notes:
- Any time a prototype is replaced, including by extension, it's a best practice to
set its constructor property back to the correct constructor. That's why we set B.prototype.constructor to B.
If you were replacing A.prototype you should do it like this:
...
A.prototype = {
constructor: A,
foo: function() {}
//other methods...
}
B.prototype = Object.create(A.prototype)
is preferred over B.prototype = new A()
because it helps you detect it early if you forgot to call A() from B()'s constructor; it also allows A() to have required parameters. You'll need a shim for older browsers; the simplest shim (although it doesn't support the full Object.create spec) is at the bottom of this page: http://javascript.crockford.com/prototypal.html.
回答5:
I use the same pattern and I like its conciseness.
About the lack of the "super" keyword, that's not really a problem. Thanks to Function.prototype.call() operator, you can call any function within the context of any object. So the sequence to call A.prototype.init() from B.prototype.init() is:
A.prototype.init.call(this, some parameters ...);
Also, don't forget that you may call A constructor from B constructor like this:
B = function(key, name) {
A.call(this, key);
this.name = name;
};
An experimented JS coder will know what happens.
So to conclude: not perfect but close enough.
回答6:
I was looking for something similar. None of the answers given really appealed to me, so I finally had a crack at it myself...
http://jsfiddle.net/tn9upue0/1/
Example Classes
- $.Animal() creates a generic animal, with a default of 4 legs, that
can be passed a name in it's options, and can describe itself.
$.Dog() is a subclass of Animal that goes "woof", and may know some
tricks. $.Cat() is a subclass of Animal that goes "meow". $.Bird() is
a subclass of Animal that has 2 legs and goes "tweet".
Class implementation
- Each animal subclass creates an instance of $.Animal called parent,
which can be used later to call methods of the parent. When calling a
parent method, context can be important. When it is, the method
should be called via $.proxy() passing this as the context.
Example output
My name is unknown. I am an animal with 4 legs.
My name is Rover. I am an animal with 4 legs. I say "woof". I can sit, stay, and roll over.
My name is Mittens. I am an animal with 4 legs. I say "meow".
My name is unknown. I am an animal with 2 legs. I say "tweet".
Sample code
$.Animal = function (options) {
return {
options: options || {},
_getName: function () {
return this.options.name || 'unknown';
},
_getLegs: function () {
return 4;
},
describe: function () {
return 'My name is ' + this._getName() + '. I am an animal with ' + this._getLegs() + ' legs.';
}
}
};
$.Dog = function (options) {
var parent = $.Animal(options);
return $.extend({}, parent, {
describe: function () {
var s = $.proxy(parent.describe, this)() + ' I say "woof".';
if (this.options.tricks) {
s += ' I can ' + this.options.tricks + '.';
}
return s;
}
});
};
$.Cat = function (options) {
var parent = $.Animal(options);
return $.extend({}, parent, {
describe: function () {
return $.proxy(parent.describe, this)() + ' I say "meow".';
}
});
};
$.Bird = function (options) {
var parent = $.Animal(options);
return $.extend({}, parent, {
_getLegs: function () {
return 2;
},
describe: function () {
return $.proxy(parent.describe, this)() + ' I say "tweet".';
}
});
};
var animal = $.Animal(),
rover = $.Dog({name: 'Rover', tricks: 'sit, stay, and roll over'}),
mittens = $.Cat({name: 'Mittens'}),
bird = $.Bird();
$('#out').html(
animal.describe() + '<br>' +
rover.describe() + '<br>' +
mittens.describe() + '<br>' +
bird.describe()
);