What operators should be declared as friends?

2020-02-17 02:48发布

问题:

In some books and often around the internet I see recommendations like "operator== should be declared as friend".

How should I understand when an operator must be declared as friend and when it should be declared as member? What are the operators that will most often need to be declared as friends besides == and <<?

回答1:

This really depends on whether a class is going to be on the left- or right-hand side of the call to operator== (or other operator). If a class is going to be on the right-hand side of the expression—and does not provide an implicit conversion to a type that can be compared with the left-hand side—you need to implement operator== as a separate function or as a friend of the class. If the operator needs to access private class data, it must be declared as a friend.

For example,

class Message {
    std::string content;
public:
    Message(const std::string& str);
    bool operator==(const std::string& rhs) const;
};

allows you to compare a message to a string

Message message("Test");
std::string msg("Test");
if (message == msg) {
    // do stuff...
}

but not the other way around

    if (msg == message) { // this won't compile

You need to declare a friend operator== inside the class

class Message {
    std::string content;
public:
    Message(const std::string& str);
    bool operator==(const std::string& rhs) const;
    friend bool operator==(const std::string& lhs, const Message& rhs);
};

or declare an implicit conversion operator to the appropriate type

class Message {
    std::string content;
public:
    Message(const std::string& str);
    bool operator==(const std::string& rhs) const;
    operator std::string() const;
};

or declare a separate function, which doesn't need to be a friend if it doesn't access private class data

bool operator==(const std::string& lhs, const Message& rhs);


回答2:

When you have your operators outside the class, both parameters can participate in implicit type conversions (whereas with operators being defined in the class body, only the right-hand operands can). Generally, that's a benefit for all the classic binary operators (i.e. ==,!=, +, -, <<, ... ).

Of course you should only declare operators friends of your class if you need to and not if they compute their result solely based on public members of the class.



回答3:

Generally, only operators which are implemented as free functions that genuinely need to access to private or protected data of the class that they operate on should be declared as friends, otherwise they should just be non-friend non-member functions.

Generally, the only operators that I implement as member functions are those that are fundamentally asymmetric and where the operands don't have equivalent roles. The ones that I tend to implement as members are those required to be members: simple assignment, (), [] and -> together with compound assignment operators, unary operators and perhaps some overloads of << and >> for classes that are themselves stream or stream-like classes. I never overload &&, || or ,.

All other operators I tend to implement as free functions, preferably using the public interface of the classes which they operate on, falling back to being friends only where necessary.

Keeping operators such as !=, ==, <, +, /, etc as non-member functions enables identical treatment of the left and right operands with respect to implicit conversion sequences which helps to reduce the number of surprising asymmetries.