How to count differences between two files on linu

问题:

I need to work with large files and must find differences between two. And I don't need the different bits, but the number of differences.

To find the number of different rows I come up with

diff --suppress-common-lines --speed-large-files -y File1 File2 | wc -l

And it works, but is there a better way to do it?

And how to count the exact number of differences (with standard tools like bash, diff, awk, sed some old version of perl)?

回答1:

diff -U 0 file1 file2 | grep -v ^@ | wc -l

That minus 2 for the two file names at the top of the diff listing. Unified format is probably a bit faster than side-by-side format.

回答2:

If you want to count the number of lines that are different use this:

diff -U 0 file1 file2 | grep ^@ | wc -l

Doesn't John's answer double count the different lines?

回答3:

If using Linux/Unix, what about comm -1 file1 file2 to print lines in file1 that aren't in file2, comm -1 file1 file2 | wc -l to count them, and similarly for comm -2 ...?

回答4:

Since every output line that differs starts with < or > character, I would suggest this:

diff file1 file2 | grep ^[\>\<] | wc -l

By using only \< or \> in the script line you can count differences only in one of the files.

回答5:

I believe the correct solution is in this answer, that is:

$ diff -y --suppress-common-lines a b | grep '^' | wc -l
1

回答6:

If you're dealing with files with analogous content that should be sorted the same line-for-line (like CSV files describing similar things) and you would e.g. want to find 2 differences in the following files:

File a:    File b:
min,max    min,max
1,5        2,5
3,4        3,4
-2,10      -1,1

you could implement it in Python like this:

different_lines = 0
with open(file1) as a, open(file2) as b:
    for line in a:
        other_line = b.readline()
        if line != other_line:
            different_lines += 1