open maps/google maps in react native

问题:

I am trying to open google maps or maps in my react-native application, but when I run the app in my Iphone/simulator I receive the error "Don't know how to open URI:...". What I am doing wrong?

My code:

openGps() {
  var url = 'geo:37.484847,-122.148386'
  this.openExternalApp(url)
}

openExternalApp(url) {
  Linking.canOpenURL(url).then(supported => {
    if (supported) {
      Linking.openURL(url);
    } else {
      console.log('Don\'t know how to open URI: ' + url);
    }
  });
}

回答1:

To open url with custom label ios/android:

const scheme = Platform.select({ ios: 'maps:0,0?q=', android: 'geo:0,0?q=' });
const latLng = `${lat},${lng}`;
const label = 'Custom Label';
const url = Platform.select({
  ios: `${scheme}${label}@${latLng}`,
  android: `${scheme}${latLng}(${label})`
});


Linking.openURL(url); 

回答2:

This is because iOS does not yet have support for geo: yet as mentioned in this SO answer. What you can do is detect the OS and:

• use geo: on Android
• handle iOS differently. Possibly use maps: as it will open up Apple Maps, though I'm unsure how to properly send the coordinates to it. Or maybe append it to a google maps HTTP URL and open it in the browser.

For example, your openGps function could look like this:

openGps = (lat, lng) => {
  var scheme = Platform.OS === 'ios' ? 'maps:' : 'geo:';
  var url = scheme + `${lat},${lng}`;
  Linking.openURL(url);
}

回答3:

you can do like this:

Android:

 <TouchableOpacity onPress={() => Linking.openURL('google.navigation:q=100+101')}>

where q is the destination lat + long

IOS:

  <TouchableOpacity onPress={() => Linking.openURL('maps://app?saddr=100+101&daddr=100+102')}>

where saddr is start address and daddr is destination address lat+long

回答4:

const latitude = "40.7127753";
const longitude = "-74.0059728";
const label = "New York, NY, USA";

const url = Platform.select({
  ios: "maps:" + latitude + "," + longitude + "?q=" + label,
  android: "geo:" + latitude + "," + longitude + "?q=" + label
});
Linking.openURL(url);

or with checking if there's a google map app on device and if not open the location in browser

const latitude = "40.7127753";
const longitude = "-74.0059728";
const label = "New York, NY, USA";

const url = Platform.select({
  ios: "maps:" + latitude + "," + longitude + "?q=" + label,
  android: "geo:" + latitude + "," + longitude + "?q=" + label
});

Linking.canOpenURL(url).then(supported => {
  if (supported) {
    return Linking.openURL(url);
  } else {
    browser_url =
      "https://www.google.de/maps/@" +
      latitude +
      "," +
      longitude +
      "?q=" +
      label;
    return Linking.openURL(browser_url);
  }
});

回答5:

Working on Android with an address using the following:

Linking.openURL('https://www.google.com/maps/search/?api=1&query=address');

Replace address with your favourite address.

回答6:

To complement other answers, here's a snippet of adding a marker on Android:

    const location = `${latitude},${longitude}`
    const url = Platform.select({
      ios: `maps:${location}`,
      android: `geo:${location}?center=${location}&q=${location}&z=16`,
    });
    Linking.openURL(url);

If you want more details about Android and google maps, here's the link for the documentation: https://developers.google.com/maps/documentation/urls/android-intents

回答7:

const url = Platform.select({
  ios: `maps:0,0?q=${fullAddress}`,
  android: `geo:0,0?q=${fullAddress}`,
})

Linking.openURL(url)