How to access OpenXML content by page number?

问题:

Using OpenXML, can I read the document content by page number?

wordDocument.MainDocumentPart.Document.Body gives content of full document.

  public void OpenWordprocessingDocumentReadonly()
        {
            string filepath = @"C:\...\test.docx";
            // Open a WordprocessingDocument based on a filepath.
            using (WordprocessingDocument wordDocument =
                WordprocessingDocument.Open(filepath, false))
            {
                // Assign a reference to the existing document body.  
                Body body = wordDocument.MainDocumentPart.Document.Body;
                int pageCount = 0;
                if (wordDocument.ExtendedFilePropertiesPart.Properties.Pages.Text != null)
                {
                    pageCount = Convert.ToInt32(wordDocument.ExtendedFilePropertiesPart.Properties.Pages.Text);
                }
                for (int i = 1; i <= pageCount; i++)
                {
                    //Read the content by page number
                }
            }
        }

MSDN Reference

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Update 1:

it looks like page breaks are set as below

<w:p w:rsidR="003328B0" w:rsidRDefault="003328B0">
        <w:r>
            <w:br w:type="page" />
        </w:r>
    </w:p>

So now I need to split the XML with above check and take InnerTex for each, that will give me page vise text.

Now question becomes how can I split the XML with above check?

---

Update 2:

Page breaks are set only when you have page breaks, but if text is floating from one page to other pages, then there is no page break XML element is set, so it revert back to same challenge how o identify the page separations.

回答1:

You cannot reference OOXML content via page numbering at the OOXML data level alone.

• Hard page breaks are not the problem; hard page breaks can be counted.
• Soft page breaks are the problem. These are calculated according to line break and pagination algorithms which are implementation dependent; it is not intrinsic to the OOXML data. There is nothing to count.

What about w:lastRenderedPageBreak, which is a record of the position of a soft page break at the time the document was last rendered? No, w:lastRenderedPageBreak does not help in general either because:

• By definition, w:lastRenderedPageBreak position is stale when content has been changed since last opened by a program that paginates its content.
• In MS Word's implementation, w:lastRenderedPageBreak is known to be unreliable in various circumstances including
  1. when table spans two pages
  2. when next page starts with an empty paragraph
  3. for multi-column layouts with text boxes starting a new column
  4. for large images or long sequences of blank lines

If you're willing to accept a dependence on Word Automation, with all of its inherent licensing and server operation limitations, then you have a chance of determining page boundaries, page numberings, page counts, etc.

Otherwise, the only real answer is to move beyond page-based referencing frameworks that are dependent upon proprietary, implementation-specific pagination algorithms.

回答2:

This is how I ended up doing it.

  public void OpenWordprocessingDocumentReadonly()
        {
            string filepath = @"C:\...\test.docx";
            // Open a WordprocessingDocument based on a filepath.
            Dictionary<int, string> pageviseContent = new Dictionary<int, string>();
            int pageCount = 0;
            using (WordprocessingDocument wordDocument =
                WordprocessingDocument.Open(filepath, false))
            {
                // Assign a reference to the existing document body.  
                Body body = wordDocument.MainDocumentPart.Document.Body;
                if (wordDocument.ExtendedFilePropertiesPart.Properties.Pages.Text != null)
                {
                    pageCount = Convert.ToInt32(wordDocument.ExtendedFilePropertiesPart.Properties.Pages.Text);
                }
                int i = 1;
                StringBuilder pageContentBuilder = new StringBuilder();
                foreach (var element in body.ChildElements)
                {
                    if (element.InnerXml.IndexOf("<w:br w:type=\"page\" />", StringComparison.OrdinalIgnoreCase) < 0)
                    {
                        pageContentBuilder.Append(element.InnerText);
                    }
                    else
                    {
                        pageviseContent.Add(i, pageContentBuilder.ToString());
                        i++;
                        pageContentBuilder = new StringBuilder();
                    }
                    if (body.LastChild == element && pageContentBuilder.Length > 0)
                    {
                        pageviseContent.Add(i, pageContentBuilder.ToString());
                    }
                }
            }
        }

Downside: This wont work in all scenarios. This will work only when you have a page break, but if you have text extended from page 1 to page 2, there is no identifier to know you are in page two.

回答3:

List<Paragraph> Allparagraphs = wp.MainDocumentPart.Document.Body.OfType<Paragraph>().ToList();

List<Paragraph> PageParagraphs = Allparagraphs.Where (x=>x.Descendants<LastRenderedPageBreak>().Count() ==1) .Select(x => x).Distinct().ToList();