Why does my program's memory not release?

2020-02-15 14:50发布

问题:

#include <iostream>
#include <string>
#include <deque>
#include <vector>
#include <unistd.h>
using namespace std;
struct Node
{
    string str;
    vector<string> vec;
    Node(){};
    ~Node(){};
};
int main ()
{
    deque<Node> deq;
    for(int i = 0; i < 100; ++i)
    {
        Node tmp;
        tmp.vec.resize(100000);
        deq.push_back(tmp);
    }
    while(!deq.empty())
    {
        deq.pop_front();
    }
    {
        deque<Node>().swap(deq);
    }
    cout<<"releas\n";
    sleep(80000000);
    return 0;
}

By top ,I found my program's memory was about 61M, why? And it's ok if there is a copy-constructor in Node.I would like to know why , not how to make it correct.

gcc (GCC) 4.9.1, centos

回答1:

Generally, new/delete and malloc/realloc/free arrange for more memory from the OS using sbrk() or OS-specific-equivalent, and divide the pages up however they like to satisfy the program's allocation requests. It's not worth the bother to try to release small pages back to the OS - too much extra overhead tracking the pages that are / are not still part of the pool, rerequesting them etc.. In low memory situations, normal caching mechanisms will allow long-unused memory pages to be swapped out of physical RAM anyway.

FWIW, GNU libC's malloc et al. makes an exception for particularly large requests so they can be fully released for the OS / other programs to use before program termination; quoting from the NOTES section here:

When allocating blocks of memory larger than MMAP_THRESHOLD bytes, the glibc malloc() implementation allocates the memory as a private anonymous mapping using mmap(2). MMAP_THRESHOLD is 128 kB by default, but is adjustable using mallopt(3). Allocations performed using mmap(2) are unaffected by the RLIMIT_DATA resource limit (see getrlimit(2)).



回答2:

If container is vector, you can use swap to release memory, container is deque, you should use clear to release memory, like this:

int main ()
{
    deque<Node> deq;
    for(int i = 0; i < 100; ++i)
    {
        Node tmp;
        tmp.vec.resize(100000);
        deq.push_back(tmp);
    }
    while(!deq.empty())
    {
        deq.pop_front();
    }
    deq.clear();
    // Or, you should try to use `deque<Node>().swap(deq);`, not `local`.

    cout<<"releas\n";
    sleep(80000000);
    return 0;
}


标签: c++ memory deque