Fill In The Date Gaps With Date Table

问题:

I have two tables.

An orders table with customer, and date. A date dimension table from a data warehouse.

The orders table does not contain activity for every date in a given month, but I need to return a result set that fills in the gaps with date and customer.

For Example, I need this:

Customer   Date
===============================
Cust1       1/15/2012   
Cust1       1/18/2012
Cust2       1/5/2012
Cust2       1/8/2012

To look like this:

Customer   Date
============================
Cust1       1/15/2012   
Cust1       1/16/2012   
Cust1       1/17/2012       
Cust1       1/18/2012
Cust2       1/5/2012
Cust2       1/6/2012
Cust2       1/7/2012
Cust2       1/8/2012

This seems like a left outer join, but it is not returning the expected results. Here is what I am using, but this is not returning every date from the date table as expected.

SELECT o.customer, 
       d.fulldate
FROM   datetable d 
       LEFT OUTER JOIN orders o 
                    ON d.fulldate = o.orderdate 
WHERE  d.calendaryear IN ( 2012 ); 

回答1:

The problem is that you need all customers for all dates. When you do the left outer join, you are getting NULL for the customer field.

The following sets up a driver table by cross joining the customer names and dates:

SELECT driver.customer, driver.fulldate, o.amount 
FROM   (select d.fulldate, customer
        from datetable d cross join
             (select customer
              from orders
              where year(orderdate) in (2012)
             ) o
        where d.calendaryear IN ( 2012 )
       ) driver LEFT OUTER JOIN
       orders o 
       ON driver.fulldate = o.orderdate and
          driver.customer = o.customer;

Note that this version assumes that calendaryear is the same as year(orderdate).

回答2:

You can use recursive CTE to get all dates between two dates without need for datetable:

;WITH CTE_MinMax AS
(
    SELECT Customer, MIN(DATE) AS MinDate, MAX(DATE) AS MaxDate
    FROM dbo.orders
    GROUP BY Customer
)
,CTE_Dates AS
(
    SELECT Customer, MinDate AS Date
    FROM CTE_MinMax
    UNION ALL
    SELECT c.Customer, DATEADD(DD,1,Date) FROM CTE_Dates c
    INNER JOIN CTE_MinMax mm ON c.Customer = mm.Customer
    WHERE DATEADD(DD,1,Date) <= mm.MaxDate
)
SELECT c.* , COALESCE(o.Amount, 0)
FROM CTE_Dates c
LEFT JOIN Orders o ON c.Customer = o.Customer AND c.Date = o.Date
ORDER BY Customer, Date
OPTION (MAXRECURSION 0)

SQLFiddle DEMO

回答3:

Here is a simple way to do it:

SELECT  A.Customer,
        B.fulldate [Date],
        ISNULL(C.Amount,0) Amount
FROM (  SELECT  Customer, 
                MIN([Date]) MinDate,
                MAX([Date]) MaxDate
        FROM Orders
        GROUP BY Customer) A
LEFT JOIN DateTable B
    ON B.fulldate BETWEEN A.MinDate AND A.MaxDate
LEFT JOIN Orders C
    ON A.Customer = C.Customer 
    AND B.fulldate = C.[Date]

回答4:

Assuming that datetable includes every date of the year you can do with one simple CTE

WITH OrdersCustomerDateBorders AS
(
    SELECT CustomerID, MIN(fulldate) AS FirstOrderDate, MAX(fulldate) AS LastOrderDate
    FROM orders
    GROUP BY customer
)
select o.customer, d.fulldate, ISNULL(o.amount, 0) AS Amount
from orders o
INNER JOIN OrdersCustomerDateBorders OCDB ON OCDB.CustomerID = o.CustomerID
INNER JOIN datetable d ON  ON d.fulldate between OCDB.FirstOrderDate AND OCDB.LastOrderDate
WHERE d.calendaryear in (2012);