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I am learning programming in C. Could you explain why nothing is printed here? Thanks in advance.
#include <stdio.h>
int main (void)
{
char a[]="abcde";
printf ("%s", a);
}
On many systems printf is buffered, i.e. when you call printf the output is placed in a buffer instead of being printed immediately. The buffer will be flushed (aka the output printed) when you print a newline \n.
On all systems your program will print despite the missing \n as the buffer is flushed when your program ends.
Typically you would still add the \n like:
printf ("%s\n", a);
An alternative way to get the output immediately is to call fflush to flush the buffer. From the man page:
For output streams, fflush() forces a write of all user-space buffered data for the given output or update stream via the stream's underlying write function.
Source: http://man7.org/linux/man-pages/man3/fflush.3.html
EDIT
As pointed out by @Barmar and quoted by @Alter Mann it is required that the buffer is flushed when the program ends.
Quote from @Alter Mann:
If the main function returns to its original caller, or if the exit function is called, all open files are closed (hence all output streams are flushed) before program termination.
See calling main() in main() in c
