I have the following vector:
x <- c(11, 12, 21, 22)
And I want to convert it to the corresponding letters, i.e., I want to get this result:
AA AB BA BB
How do I make this? I bet there's a simple answer and that it goes through using the reserved LETTERS
vector, but I can't figure out a solution. This is the best I've managed to come up with so far (you might want to take the kids out of the room):
> paste0(gsub(1, LETTERS[1], substr(x, 1, 1)),
gsub(2, LETTERS[2], substr(x, 1, 1)))
[1] "A1" "A1" "2B" "2B"
Since this just involves one-to-one character substitution, it might be simplest to just use chartr()
chartr("123456789", "ABCDEFGHI", x)
# [1] "AA" "AB" "BA" "BB"
Without libraries, the compact one-line solution is
sapply(strsplit(paste(x),''), function(y) paste(LETTERS[as.numeric(y)], collapse = ''))
# [1] "AA" "AB" "BA" "BB"
Like this?
x <- c(11, 12, 21, 22)
s1 = as.numeric(substr(x, start=1, stop=1))
s2 = as.numeric(substr(x, start=2, stop=2))
print(paste0(LETTERS[s1], LETTERS[s2]))
>[1] "AA" "AB" "BA" "BB"
or like this:
sapply(strsplit(as.character(c(123,11,22,5612)),""), function(x) paste0(LETTERS[as.integer(x)], collapse=""))
## [1] "ABC" "AA" "BB" "EFAB"