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问题:
Since arrays and hashes can only contain scalars in Perl, why do you have to use the $ to tell the interpreter that the value is a scalar when accessing array or hash elements? In other words, assuming you have an array @myarray
and a hash %myhash
, why do you need to do:
$x = $myarray[1];
$y = $myhash{'foo'};
instead of just doing :
$x = myarray[1];
$y = myhash{'foo'};
Why are the above ambiguous?
Wouldn't it be illegal Perl code if it was anything but a $ in that place? For example, aren't all of the following illegal in Perl?
@var[0];
@var{'key'};
%var[0];
%var{'key'};
回答1:
Slices aren't illegal:
@slice = @myarray[1, 2, 5];
@slice = @myhash{qw/foo bar baz/};
And I suspect that's part of the reason why you need to specify if you want to get a single value out of the hash/array or not.
回答2:
I've just used
my $x = myarray[1];
in a program and, to my surprise, here's what happened when I ran it:
$ perl foo.pl
Flying Butt Monkeys!
That's because the whole program looks like this:
$ cat foo.pl
#!/usr/bin/env perl
use strict;
use warnings;
sub myarray {
print "Flying Butt Monkeys!\n";
}
my $x = myarray[1];
So myarray calls a subroutine passing it a reference to an anonymous array containing a single element, 1.
That's another reason you need the sigil on an array access.
回答3:
The sigil give you the return type of the container. So if something starts with @
, you know that it returns a list. If it starts with $
, it returns a scalar.
Now if there is only an identifier after the sigil (like $foo
or @foo
, then it's a simple variable access. If it's followed by a [
, it is an access on an array, if it's followed by a {
, it's an access on a hash.
# variables
$foo
@foo
# accesses
$stuff{blubb} # accesses %stuff, returns a scalar
@stuff{@list} # accesses %stuff, returns an array
$stuff[blubb] # accesses @stuff, returns a scalar
# (and calls the blubb() function)
@stuff[blubb] # accesses @stuff, returns an array
Some human languages have very similar concepts.
However many programmers found that confusing, so Perl 6 uses an invariant sigil.
In general the Perl 5 compiler wants to know at compile time if something is in list or in scalar context, so without the leading sigil some terms would become ambiguous.
回答4:
This is valid Perl: @var[0]
. It is an array slice of length one. @var[0,1]
would be an array slice of length two.
@var['key']
is not valid Perl because arrays can only be indexed by numbers, and
the other two (%var[0] and %var['key']
) are not valid Perl because hash slices use the {} to index the hash.
@var{'key'}
and @var{0}
are both valid hash slices, though. Obviously it isn't normal to take slices of length one, but it is certainly valid.
See the slice section of perldata perldocfor more information about slicing in Perl.
回答5:
People have already pointed out that you can have slices and contexts, but sigils are there to separate the things that are variables from everything else. You don't have to know all of the keywords or subroutine names to choose a sensible variable name. It's one of the big things I miss about Perl in other languages.
回答6:
I can think of one way that
$x = myarray[1];
is ambiguous - what if you wanted a array called m?
$x = m[1];
How can you tell that apart from a regex match?
In other words, the syntax is there to help the Perl interpreter, well, interpret!
回答7:
In Perl 5 (to be changed in Perl 6) a sigil indicates the context of your expression.
- You want a particular scalar out of a hash so it's
$hash{key}
.
- You want the value of a particular slot out of an array, so it's
$array[0]
.
However, as pointed out by zigdon, slices are legal. They interpret the those expressions in a list context.
- You want a lists of 1 value in a hash
@hash{key}
works
But also larger lists work as well, like @hash{qw<key1 key2 ... key_n>}
.
You want a couple of slots out of an array @array[0,3,5..7,$n..$n+5]
works
@array[0]
is a list of size 1.
There is no "hash context", so neither %hash{@keys}
nor %hash{key}
has meaning.
So you have "@"
+ "array[0]"
<=> < sigil = context > + < indexing expression > as the complete expression.
回答8:
The sigil provides the context for the access:
$
means scalar context (a scalar
variable or a single element of a hash or an array)
@
means list context (a whole array or a slice of
a hash or an array)
%
is an entire hash
回答9:
In Perl 5 you need the sigils ($ and @) because the default interpretation of bareword identifier is that of a subroutine call (thus eliminating the need to use & in most cases ).