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PHP: How to encode infinity or NaN numbers to JSON

2019-01-20 08:13发布

问题:

Apparently, infinity and NaN are not a part of JSON specification, so this PHP code:

$numbers = array();
$numbers ['positive_infinity'] = +INF;
$numbers ['negative_infinity'] = -INF;
$numbers ['not_a_number'] = NAN;
$array_print = print_r ($numbers, true);
$array_json = json_encode ($numbers);
echo "\nprint_r(): $array_print";
echo "\njson_encode(): $array_json";

Produces this:

PHP Warning:  json_encode(): double INF does not conform to the JSON spec, encoded as 0 in /home/septi/test.php on line 8
PHP Warning:  json_encode(): double -INF does not conform to the JSON spec, encoded as 0 in /home/septi/test.php on line 8
PHP Warning:  json_encode(): double NAN does not conform to the JSON spec, encoded as 0 in /home/septi/test.php on line 8

print_r(): Array
(
    [positive_infinity] => INF
    [negative_infinity] => -INF
    [not_a_number] => NAN
)

json_encode(): {"positive_infinity":0,"negative_infinity":0,"not_a_number":0}

Is there any way to correctly encode these numbers without writing my own json_encode() function? Maybe some workaround?

回答1:

According to JSON spec, there is no Infinity or NaN values: http://json.org/

Workarounds:

  1. Reject using JSON (pure JSON), and write your own json_encode function, which will handle INF/NAN (converting to "Infinity" and "NaN" respectively), and make sure you are parsing JSON using something like result = eval('(' + json + ')'); on the client side.

  2. Pre convert your IFN/NAN values into string values ('Infinity' and 'NaN'), and when you are going to operate with those values in JavaScript, use the following construction: var number1 = (+numbers.positive_infinity);. This will convert string value 'Infinity' into numeric Infinity representation.



回答2:

This is in my opinion a big shortcoming of JSON. Different JSON encoders handle this differently, a quick overview can be found here: http://lavag.org/topic/16217-cr-json-labview/?p=99058

One solution is to encode +inf as +1e9999 as that will naturally overflow to +inf in most decoders, and same with -inf as -1e9999. NaN is much harder.



回答3:

You are right about the JSON spec:

Numeric values that cannot be represented as sequences of digits (such as Infinity and NaN) are not permitted.

The solution must also come from the spec, since a custom "JSON" encoder would not produce valid JSON anyway (you would have to write a custom decoder as well, and then you and consumers of your data would be forced to use that until the end of time).

Here' what the spec allows for values:

A JSON value MUST be an object, array, number, or string, or one of the following three literal names:

false null true

So, any workaround that involves legal JSON instead of a custom JSON-like protocol would involve using something else instead of numbers.

One reasonable option would be to use the strings "Infinity" and "NaN" for these edge cases.



回答4:

The warning mentioned above, there is official bug reported in php documentation.

https://bugs.php.net/bug.php?id=64695



回答5:

As an update to readers of this question for newer versions of PHP >= 5.5.0, to get INF or NAN values from json_encode to be encoded as 0 rather than json_encode failing to output at all, add the JSON_PARTIAL_OUTPUT_ON_ERROR option.

As an example: json_encode($data, JSON_NUMERIC_CHECK | JSON_PARTIAL_OUTPUT_ON_ERROR);