Suppose I want to generate ------
, with only -
, is there a C macro to generate repeated string ?
问题:
回答1:
use boost, E.g
#include <stdio.h>
#include <boost/preprocessor/repetition/repeat.hpp>
#define Fold(z, n, text) text
#define STRREP(str, n) BOOST_PP_REPEAT(n, Fold, str)
int main(){
printf("%s\n", STRREP("-", 6));
return 0;
}
回答2:
Yes and no. It's not simple, and not generally a good idea, but you can do it for finite, constant sizes, and for constant characters. There are many ways to do this with the C preprocessor. Here is one:
#define DUP(n,c) DUP ## n ( c )
#define DUP7(c) c c c c c c c
#define DUP6(c) c c c c c c
#define DUP5(c) c c c c c
#define DUP4(c) c c c c
#define DUP3(c) c c c
#define DUP2(c) c c
#define DUP1(c) c
#include <stdio.h>
int main(int argc, char** argv)
{
printf("%s\n", DUP(5,"-"));
printf("%s\n", DUP(7,"-"));
return 0;
}
It's not pretty, and only useful when you really want the string to be stored as static (constant) data. Both the n
and 'c' parameters to DUP
have to be a constants (they cannot be variables). The Boost.Preprocessor module has a lot of good information for how and when to (ab)use the C/C++ preprocessor like this. Although Boost is a C++ library, the preprocessor information is largely applicable to straight C.
In general, you're much better off doing this in normal C code:
/* In C99 (or C++) you could declare this:
static inline char* dupchar(int c, int n)
in the hopes that the compiler will inline. C89 does not support inline
functions, although many compilers offered (inconsistent) extensions for
inlining. */
char* dupchar(int c, int n)
{
int i;
char* s;
s = malloc(n + 1); /* need +1 for null character to terminate string */
if (s != NULL) {
for(i=0; i < n; i++) s[i] = c;
}
return s;
}
or, use memset
, as @Jack suggested.
回答3:
Not in C standard.You need to write your own implementation.
EDIT:
something like this:
#include <stdio.h>
#include <string.h>
#define REPEAT(buf, size, ch) memset(&buf, ch, size)
int main(void)
{
char str[10] = { 0 };
REPEAT(str, 9, '-');
printf("%s\n", str); //---------
return 0;
}