I want to write a helper for a submit button, that takes in account the action (create or update) to get the right translation. Here they are :
fr:
submit:
create:
user: "Créer mon compte"
product: "Déposer l'objet"
session: "Se connecter"
update:
user: "Mettre à jour mon compte"
product: "Modifier l'objet"
I tried this :
def submit_button(model)
if model == nil
I18n.t('submit.create.%{model}')
else
I18n.t('submit.update.%{model}')
end
end
But it didn't worked and rspec send me that :
Capybara::ElementNotFound: Unable to find button ...
I know that's a syntactical problem, but I don't find how to make this work...
You don't need a helper for that, you can achieve it with plain rails. The only thing you need is to properly order your I18n YAML
fr:
helpers:
submit:
# This will be the default ones, will take effect if no other
# are specifically defined for the models.
create: "Créer %{model}"
update: "Modifier %{model}"
# Those will however take effect for all the other models below
# for which we define a specific label.
user:
create: "Créer mon compte"
update: "Mettre à jour mon compte"
product:
create: "Déposer l'objet"
update: "Modifier l'objet"
session:
create: "Se connecter"
After that, you only need to define your submit button like this:
<%= f.submit class: 'any class you want to apply' %>
Rails will take the label you need for the button.
You can see some more info about it here
def submit_button(model)
if model == nil
I18n.t("submit.create.#{model}")
else
I18n.t("submit.update.#{model}")
end
end
The %{} is used in en.yml file when you send a local variable from helper or view.
You need the name of the model not the model object itself.
Try the following:
def submit_button(model)
model_name = model.class.name.underscore
if model.new_record?
I18n.t("submit.create.#{model_name}")
else
I18n.t("submit.update.#{model_name}")
end
end
model must not be nil in a form.
