I'm having some trouble trying to convert a fairly complex gradient, into a mixin for SASS, most gradients are fine, and I believe my colour stops are also correct, I believe it's the positioning that my MIXIN doesn't let me do this (left top, right bottom).
I need this:
.progress.stripes.animate > .bar > span {
background-image: -webkit-gradient(
linear, left top, right bottom,
color-stop(.25, rgba(255, 255, 255, .2)),
color-stop(.25, transparent),
color-stop(.5, transparent),
color-stop(.5, rgba(255, 255, 255, .2)),
color-stop(.75, rgba(255, 255, 255, .2)),
color-stop(.75, transparent), to(transparent));
background-image: -moz-linear-gradient(-45deg, rgba(255, 255, 255, .2) 25%, transparent 25%, transparent 50%, rgba(255, 255, 255, .2) 50%, rgba(255, 255, 255, .2) 75%, transparent 75%, transparent);
}
To work with this mixin:
@mixin linear-gradient($gradientLine, $colorStops...) {
background-color: nth($colorStops,1);
background-image: -webkit-gradient(linear, $gradientLine, $colorStops);
background-image: -webkit-linear-gradient($gradientLine, $colorStops);
background-image: -moz-linear-gradient($gradientLine, $colorStops);
background-image: -o-linear-gradient($gradientLine, $colorStops);
background: -ms-linear-gradient($gradientLine, $colorStops);
@if length($colorStops) == 2 {
$colour1:nth($colorStops,1);
$colour2:nth($colorStops,2);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#{$colour1}', endColorstr='#{$colour2}',GradientType=0 );
}
@if length($gradientLine) == 2 {
background-image: linear-gradient(to #{inverse-side(nth($gradientLine, 1))} #{inverse-side(nth($gradientLine, 2))}, $colorStops);
} @else {
background-image: linear-gradient(to #{inverse-side($gradientLine)}, $colorStops);
}
}
This is what I've tried but it doesn't work...
$grad: rgba(255, 255, 255, .2);
.progress.stripes.animate > .bar > span {
@include linear-gradient((left top, right bottom),$grad 25%, $transparent 25%, $transparent 5%, $grad 5%, $grad 75%, $transparent 75%);
}