How I print these UTF-8 characters in C++?
问题:
回答1:
Well, you know it is possible because your browser could render them. On Windows you can use the charmap.exe applet to discover their Unicode code points:
- ♠ = 0x2660
- ♣ = 0x2663
- ♥ = 0x2665
- ♦ = 0x2666
The challenge is to get a C/C++ program to display them. That's not going to be possible in any kind of non-platform specific way unless you use a cross-platform UI library like Qt or wxWidgets. In a Windows GUI program you can do it like this in the WM_PAINT message handler:
case WM_PAINT: {
hdc = BeginPaint(hWnd, &ps);
HFONT hFont = CreateFont(16, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, L"Arial Unicode MS");
HGDIOBJ oldFont = SelectObject(hdc, hFont);
RECT rc = {0, 0, 666, 16};
DrawTextEx(hdc, L"\x2660\x2663\x2665\x2666", -1, &rc, DT_LEFT, 0);
SelectObject(hdc, oldFont);
DeleteObject(hFont);
EndPaint(hWnd, &ps);
}
break;
回答2:
Just output the appropriate bytes to your terminal, and make sure the terminal is using a UTF-8 encoding to display your data. C++ itself is relatively UTF8-agnostic. It's just an array of uint_8's.
(Unless you want to use some sort of character-oriented operations on strings with UTF-8. Then you need to use UTF-8 manipulation functions, instead of array indexes and the normal string manipulation routines.)
e.g. sprintf("%c%c%c\n", 0xE2, 0x99, 0xA0);
回答3:
In C++: std::wcout << L"wstr [" << wstr << L']' << std::endl;
In C: printf("%ls\n\n",wstr);